Oct 02 P3 maths

[Click]

Can some one plz help me with the questions....
Q 5 ii.... found 60.4 but unable to obtain the other value... ?
Q 5 iii.... ?
Q 7 i, ii, iii..... ?

 

[CaptainDanger]

Sure someone will...

 

[diwash]

Qno 5(II)

 

[diwash]

Qno 5(III)

 

[diwash]

Qno7 (I)

 

[diwash]

Qno 7 (II)

 

[diwash]

Qno7 (III)

Hope this helped...

 

[Click]

Thanks alot diwash! That sure did help but in Q5 part iii the the greatest value is 1 not 1/6...?(sort of confused on this bit)

 

[diwash]

oh sory dude..

 

[Amna]

for Q5 (iii):

to find the greatest value of a fraction, we need to find the least value of the denominator.
so the denominator we have here is (4sinθ -3cosθ +6) which, as we found out in (i) can also be written as [5sin(θ-36.9)] so now the denominator is [ 5sin(θ-36.9) + 6 ] since the least value for sin(θ-36.9) is -1, the least value for 5sin(θ-36.9) is -5. so the least value for the whole denominator then is (-5 + 6 = 1). take the reciprocal (well, it doesn't matter in this case but in other questions it might ) and the greatest value of 1/(4sinθ -3cosθ +6) is 1.

i hope that's the right answer, i didn't check...