P1 9709 AS (ZONE 4) OCT NOV 2019

[pranavbaluguri]

How did it go for you guys?

 

[Roshan Nepal]

Do you remember the answers?

 

[pranavbaluguri]

Do you remember the answers?

Circular Measure = area of shaded region is 34.25 cm^2
Vectors = angle between the two is 53.4 degrees
Last Integration question = B (0,3/4)
Functions = least value is -7
Volume of cone = statinary value of 5√3 was a maximum as second derivitive was -6h
Sequences and series = a. sum of all days = 525; b.sum to inifinity = 27, a=9, r= 2/3

Thats all I remember, add or correct if you have any;
but yeah I am expecting a 65, i messed up, the paper difficulty was on par to what you would expect, the trig question tripped me and ran out of time too.

 

[Thought blocker]

Are u both frm India?
Are you about to enter in A level??

 

[KashishV]

These are my answers-
1) a= -4
2) 3y+2x=14
3)y=5root(X) - 6

[ I don't remember the order here onwards so I'm just categorizing the questions according to the chapter]

4) the vector question
*PB= 5i+8j-5k
*PQ=4i+8j+5k
* closer to Q than B
* angle was something like 57.4

5) the circle question
*perimeter= 2r(@+tan@) (assuming that @ is theta for simplicity lol)
*shaded area was around 34.3 ish

6) calculus-volume question
*proved that question
*h= root(75)=8.66cm; volume is 1360 (this part might be unnecessary but I calculated it to be on the safe side); Maximum value

7) series question
*37 km on day 21
*525 km overall
*(geometric series) x=9
*r=2/3 and therefore t4= 8/3
*sum to infinity is 27

8) function(s) questions
*k is 7/2 for the line to be a tangent
*-1<x<4 for f(x)>G(x) (I don't remember if it was greater than or less than)
*G{inv}f(x) = 2x^2+8x and so solving gives x=0 and x= -4
*5 (cos^2x)- 2
*a= -2 and b= -7 (this was the question where they asked us to do completing squares) least value as f(x)<= -7
* I think there was another range question- something like [-2,3] I'm sure abt upper limit being 3 but I dont remember the lower limit

9) calculus question
*dy/dx= 16/ (2x+1)^3
*int. y dx = x+(2/(2x+1))+c
*B was (0,.25) i think and A was (0.5,0) equation of normal was something like y= -0.5x+0.25
* area was (1/16)+(1/2)= 9/16 (i got this wrong, i subtracted instead of adding ugh)

10)trigonometry question
*3tan(2x+1)=1, we had to find the smallest values-- x= 1.23 rad and 2.80 rad

Hope the paper went well!