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yup!umm ya..its a lil confusing, so when ever thy ask best fit does tat mean da graph can b curve too??? i rely dnt knw!!
umm the line of best fit does not necessarily have to be a "straight line" it just has to show GENERALLY what pattern the results of an experiment follow..and it can be like a sort of an average line.. and neither does it have to pass 'most' points.. it should have an equal displacement of points around it... umm mtlb there should be around the same number of points above the line as below it.. hope i helpedLine of best is not the straight line, its the line with the most points on it
did that help?
do read some older key points noteswhen they ask us to calculate solubility and say :
"The units of solubility are grams per one hundred grams of water (g / 100g water)." What does this mean???? and what formula do we use?
thanx in advance
can u give me an example????????????????Quenching is basically stopping the reaction! Or slowing it down so much that it won't change when you measure it for example placing an amount of solution on ice
By cross multiplying, brother.Can you please tell how you calculated the concentration of the acid after calculating the moles of succinic acid?
Oui.. sorry i am not xhizors but wait till he respondsxhizors.
I wanted to confirm the method for determining solubility of a substance.
Can we take different masses of the substance In a fixed volume of water (let's say 100cm3) , and stir the solution at a fixed temperature until no more dissolves. Then allow the solution to cool while stirring and note the temperature at which the first crystals appear.
oui as in french for yes.. OMG a french speaking arabicOui.. sorry i am not xhizors but wait till he responds
umm ya..its a lil confusing, so when ever thy ask best fit does tat mean da graph can b curve too??? i rely dnt knw!!
umm the line of best fit does not necessarily have to be a "straight line" it just has to show GENERALLY what pattern the results of an experiment follow..and it can be like a sort of an average line.. and neither does it have to pass 'most' points.. it should have an equal displacement of points around it... umm mtlb there should be around the same number of points above the line as below it.. hope i helped
Thanx bro.......okay listen... go back to the ms.. not the appendix the place where its written "correctly calculates the ratio....."
the place where it says "see appendix" look above it it says what ? "calculation MUST be to 2 decimal places"
ohh since ur axis is diff frm mine, im nt rely sure hw to do it. bt fr my graph ths is hw i gt it...my x axis ws mass of carbonate n y- mass of CuO
so u gt a point in da graph n read its values ... mine were x-4.4 y-3.05
frst find the moles of CuO. (mr=79.5) do divide 3.05/79.5= 0.038
consider ratio of CuO : CuCo3
2 :1
so 0.038---> x
find x. i.e 0.038/2=0.0192 of mols of carbonate. usin ths fnd the mr of the crbonate i.e. mols=mass/mr, calculated value will b 229.4
nw to fnd da mr of the CuCO3.Cu(OH)2.xH2O, mr of ths= 221+18x
221+18x=229.4
x=0.46 whch is appro=0.5
i knw its a mess, bt hope u gt it sumhw..i rely dnt knw hw to do fr ur graph!
mines graph is same too but the point is solubility is coming more than 100g shed light plzthis is my graph.. u rely havin troubl wit tat qustn ha..hope it hlps!!
xhizors could you help me out a bit in part (e) of ON 2007 Q1? All I'm confused about is why are the moles specified to 0.05-.25?
LOL you actually confused me !oh its like since the gradient of line is constant, umm if from your construction line you find that with one unit of x you have 2 units of y... so umm 2 units of x would give you 4 units of y.
( umm another way of saying it is like 'A man walks seven miles in two hours. What is his average speed? so since his speed is constant, you half the x (time), and half the y(distance).. you have 3.5 miles/hour !)
sorry if i confused you..
no u have to draw a curve for lower temperatures!Omg,thankyou soo much!!! Turns out my coordinates were correct,i just drew curves instead of lines! :/
Yes,i was really stressed out after doing this qn! Really helped! Thanks again!
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