Physics 9702

[slayers]

I need Your Help to solve these Problem ?
Physics 9702_May/june 2009_p1 Qusetion no.15????

 

[tanmaydube]

the total mass remains the same but that its centre of gravity will only be 1⁄4h above the base after the tap is opened.
So p.e.=m*g*1/4h=mgh/4
So the answer is B.

 

[tanmaydube]

It is B because it will only reach half the value of h and the transfer of water from vessel X to vessel Y will stop. So since only water is transferred of height h/2 putting the value of h = h/2 in P.E = mgh and also since only half of the mass of water is transferred then m = m/2 so putting this in the equation of P.E = mgh

P.E (lost) = (m/2) x(g) x (h/2)
P.E (lost) = mgh/4

 

[slayers]

Thanks Guys, I got that i missed a silly point..

 

[Tsogbadrakh]

I need Your Help to solve these Problem ?
Physics 9702_May/june 2009_p1 Qusetion no.15????