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Nope i dun think so .. I also cut a few times in the ppr, but did it with a pencilDo we get penalised for cutting?
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Nope i dun think so .. I also cut a few times in the ppr, but did it with a pencilDo we get penalised for cutting?
Lol uhm, cutting as in crossing out your answer and rewriting it above.Cutting what?
Ahan okay, thanks. ^^,Nope i dun think so .. I also cut a few times in the ppr, but did it with a pencil
Noo.. they are not that mean. As long u wrote the answer in the space. It is correctLol uhm, cutting as in crossing out your answer and rewriting it above.
No penalty is applied on crossing neatly through any answer which you do not think is appropriate. You can cross it out with a pencil or a pen, but clearly, otherwise if it is visible, the part which you have crossed out may be marked. After crossing out something, it is better to write it after the crossed out portion rather than above it, as it is difficult for examiners to go through it. However no marks are deducted due to this.Lol uhm, cutting as in crossing out your answer and rewriting it above.
No probAhan okay, thanks. ^^,
Noo.. they are not that mean. As long u wrote the answer in the space. It is correct
Okay, huge relief. :$No penalty is applied on crossing neatly through any answer which you do not think is appropriate. You can cross it out with a pencil or a pen, but clearly, otherwise if it is visible, the part which you have crossed out may be marked. After crossing out something, it is better to write it after the crossed out portion rather than above it, as it is difficult for examiners to go through it. However no marks are deducted due to this.
voltmeter itself is of high resistanceA resistor is included to prevent short circuit
no this wnt be aceptedi wrote about using a retractable steel tape to measure that distance by mark off points where the tape finishes and starting all over from that point until the complete distance is measured. However, few friends of mine mentioned: COVERING THE SAME DISTANCE IN A CAR AND NOTING DOWN THE DISTANCE COVERED. DOES ANYONE KNOW WHETHER THAT'S ACCEPTABLE? (THOUGH ITS NON-PHYSICS) and CARS GUVE DISTANCE IN KILOMETERS, THEY ARE QUITE INACCURATE AS WELL.
koi faida nahi behs ka jab marking scheme aaye gi tab dekha jaye ga.....and even then not all possible answers are given in the marking scheme...no this wnt be acepted
no this wnt be acepted
I did what you did.. So same question from me..in that focal length part, i chose the coordinates (10,10) hence got the focal length of 5 cm, although my graph did pass through the points (20,20). I REALLY HOPE MY ANSWER IS NOT WRONG. ANY CLUE?
no this is wrong, u made the graph pass through (20,20), it actually passed through (20,19.8)....do not assume values theoretically....in that focal length part, i chose the coordinates (10,10) hence got the focal length of 5 cm, although my graph did pass through the points (20,20). I REALLY HOPE MY ANSWER IS NOT WRONG. ANY CLUE?
and listen even if u made a mistake, there is not time to think and fret over it, try and do better in the next paper.in that focal length part, i chose the coordinates (10,10) hence got the focal length of 5 cm, although my graph did pass through the points (20,20). I REALLY HOPE MY ANSWER IS NOT WRONG. ANY CLUE?
and listen even if u made a mistake, there is not time to think and fret over it, try and do better in the next paper.
i think my y co-ordinate was somewhat close to 19.8 in the graph.no this is wrong, u made the graph pass through (20,20), it actually passed through (20,19.8)....do not assume values theoretically....
the focal length was 10, not 5
the 19.8 can be rounded off to 20...it is arbitarily very close to 20.... so 20/2=10....i think my y co-ordinate was somewhat close to 19.8 in the graph.
Well, in that case u is not equal to y.
how could you then use the u value of 10 in that formula they had stated to find the focal length taking the coordinates(20,19.8) u had to be equal to v for that formula to work.
and the question said in theory, so it can be assumed that 19.8 is arbitarily close 20.i think my y co-ordinate was somewhat close to 19.8 in the graph.
Well, in that case u is not equal to y.
how could you then use the u value of 10 in that formula they had stated to find the focal length taking the coordinates(20,19.8) u had to be equal to v for that formula to work.
I have to agree!a
and the question said in theory, so it can be assumed that 19.8 is arbitarily close 20.
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