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Physics ATP disussion

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Lol uhm, cutting as in crossing out your answer and rewriting it above.
No penalty is applied on crossing neatly through any answer which you do not think is appropriate. You can cross it out with a pencil or a pen, but clearly, otherwise if it is visible, the part which you have crossed out may be marked. After crossing out something, it is better to write it after the crossed out portion rather than above it, as it is difficult for examiners to go through it. However no marks are deducted due to this.
 
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Noo.. they are not that mean. As long u wrote the answer in the space. It is correct
No penalty is applied on crossing neatly through any answer which you do not think is appropriate. You can cross it out with a pencil or a pen, but clearly, otherwise if it is visible, the part which you have crossed out may be marked. After crossing out something, it is better to write it after the crossed out portion rather than above it, as it is difficult for examiners to go through it. However no marks are deducted due to this.
Okay, huge relief. :$
 
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i wrote about using a retractable steel tape to measure that distance by mark off points where the tape finishes and starting all over from that point until the complete distance is measured. However, few friends of mine mentioned: COVERING THE SAME DISTANCE IN A CAR AND NOTING DOWN THE DISTANCE COVERED. DOES ANYONE KNOW WHETHER THAT'S ACCEPTABLE? (THOUGH ITS NON-PHYSICS) and CARS GUVE DISTANCE IN KILOMETERS, THEY ARE QUITE INACCURATE AS WELL.
 
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For all those saying that a resistor needed to be added to the circuit; if a resistor was added then there should have been a separate voltmeter for the solar cell connected ACROSS it since the potential difference across each component is different. When asked to measure the E.M.F of a cell, we connect a voltmeter directly across it, with NO resistor. The only purpose they told us to add a SWITCH was to check our knowledge of symbols.
 
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i wrote about using a retractable steel tape to measure that distance by mark off points where the tape finishes and starting all over from that point until the complete distance is measured. However, few friends of mine mentioned: COVERING THE SAME DISTANCE IN A CAR AND NOTING DOWN THE DISTANCE COVERED. DOES ANYONE KNOW WHETHER THAT'S ACCEPTABLE? (THOUGH ITS NON-PHYSICS) and CARS GUVE DISTANCE IN KILOMETERS, THEY ARE QUITE INACCURATE AS WELL.
no this wnt be acepted
 
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no this wnt be acepted

in that focal length part, i chose the coordinates (10,10) hence got the focal length of 5 cm, although my graph did pass through the points (20,20). I REALLY HOPE MY ANSWER IS NOT WRONG. ANY CLUE?
 
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in that focal length part, i chose the coordinates (10,10) hence got the focal length of 5 cm, although my graph did pass through the points (20,20). I REALLY HOPE MY ANSWER IS NOT WRONG. ANY CLUE?
I did what you did.. So same question from me..
 
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in that focal length part, i chose the coordinates (10,10) hence got the focal length of 5 cm, although my graph did pass through the points (20,20). I REALLY HOPE MY ANSWER IS NOT WRONG. ANY CLUE?
no this is wrong, u made the graph pass through (20,20), it actually passed through (20,19.8)....do not assume values theoretically....
the focal length was 10, not 5
 
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in that focal length part, i chose the coordinates (10,10) hence got the focal length of 5 cm, although my graph did pass through the points (20,20). I REALLY HOPE MY ANSWER IS NOT WRONG. ANY CLUE?
and listen even if u made a mistake, there is not time to think and fret over it, try and do better in the next paper.
 
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and listen even if u made a mistake, there is not time to think and fret over it, try and do better in the next paper.
no this is wrong, u made the graph pass through (20,20), it actually passed through (20,19.8)....do not assume values theoretically....
the focal length was 10, not 5
i think my y co-ordinate was somewhat close to 19.8 in the graph.
Well, in that case u is not equal to y.
how could you then use the u value of 10 in that formula they had stated to find the focal length taking the coordinates(20,19.8) u had to be equal to v for that formula to work.
 
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i think my y co-ordinate was somewhat close to 19.8 in the graph.
Well, in that case u is not equal to y.
how could you then use the u value of 10 in that formula they had stated to find the focal length taking the coordinates(20,19.8) u had to be equal to v for that formula to work.
the 19.8 can be rounded off to 20...it is arbitarily very close to 20.... so 20/2=10....
however in the case of your curve, the curve may be accepted and no mark will be deducted...however the focal legth is not 5
 
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i think my y co-ordinate was somewhat close to 19.8 in the graph.
Well, in that case u is not equal to y.
how could you then use the u value of 10 in that formula they had stated to find the focal length taking the coordinates(20,19.8) u had to be equal to v for that formula to work.
and the question said in theory, so it can be assumed that 19.8 is arbitarily close 20.
 
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and the question said in theory, so it can be assumed that 19.8 is arbitarily close 20.
I have to agree!
and thought Physics my ATP went great! :(
I lost two marks in one go. Anyhoo, I'm not all tears-and-cries over it. Just quite depressed over letting my handwork go wasted over a petty technical thing like that. Wish u the best grade tho!
 
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