Even I have a doubt in thatSomeone help me solve part (c)...
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Even I have a doubt in thatSomeone help me solve part (c)...
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Paper 31 or 32..? The link u have provided is for may/June...not Oct/Nov.Can someone please explain oct nov 2009 paper 3 question 9 part b(i) and (ii)
Link:- https://drive.google.com/folderview...sp=drive_web&tid=0BzumkDfi9230NFdPdmpOTjFfeHM
Thank you in advance
G3?Someone help me solve part (c)...
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Hope u'll get it...Can someone explain oct nov 2011 qp 32 question 3 part c also
Link:- https://drive.google.com/folderview...sp=drive_web&tid=0BzumkDfi9230NFdPdmpOTjFfeHM
Thank you in advance
its answer is 1.5 and the reason is simpleSomeone help me solve part (c)...
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lol i am wrong srry....... ill try to solve it again........O/N 2005
O/N 2005
YEA he is right i did not read your answer first i just directly replied to himG3?
So yeah one of the conditions of equilibrium is no resultant force. Therefore forces up = forces down
Forces up = 8N
Forces down = 1.5N + 6N = 7.5N
These are not equal.
To make them equal there must be a force acting downwards, of magnitude 0.5N.
I didAnyone did 31?
Sorry I needed may june not oct/nov. I edited my postPaper 31 or 32..? The link u have provided is for may/June...not Oct/Nov.
I understood the first two but the last part marking scheme says 5.24 and they subtracted 14.7 from 30.9(which I did not understand why)Hope u'll get it...View attachment 53900
It is CO2 and H2O. In the presence of oxygen it undergoes aerobic respiration. C2H5OH + 3O2 --> 2CO2 + 3H2O .yeah i wrote that but some of my friends suggests that it will produce co2 and water
I understood the first two but the last part marking scheme says 5.24 and they subtracted 14.7 from 30.9(which I did not understand why)
can someone help me ? explanation also pleaseView attachment 53903
Could somebody do part (b)
Like a complete diagram please!
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