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Physics, Chemistry and Biology: Post your doubts here!

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Hi guys. I wanted to ask that do I have to show my working in the IGCSE Physics Paper 1 Multiple Choice Paper. (you know like how I got the answer to them?)

Any help will be warmly appreciated.

THANKS
 
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Hey, did the enterprise paper of 2013 winter come out anybody. If it did and u see it, please can you give it to me. I really need it. Thanks in advance. :)
 
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A question here. When does Xtremepapers start uploading all the 2013 past papers for IGCSE onto the site? I thought they'd be uploaded by now..
 
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Hi guys may anyone give me a guide on how to complete this. Please anyone or any easy way to complete these.
 

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1) How can you measure diametre of cylindrical rod using thread?
2)How can you find resistance of a wire using ohm's law and electrical instruments?
Awesome12
fantastic girl
shazmina
***amd***
Iridescent
1) Roll the thread over the cylindrical rod n measure the length of the thread for one complete roll
or roll it many times....then find the length of the thread and divide the answer by the no. of rolls u made
 
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1) How can you measure diametre of cylindrical rod using thread?
2)How can you find resistance of a wire using ohm's law and electrical instruments?
Awesome12
fantastic girl
shazmina
***amd***
Iridescent
2) * Keep the rheostat/variable resistor in the maximum resistant position before closing the switch of the circuit
* Close the switch and move the rheostat to different positions and note the Voltage and current value
* Plot the graph of V in y axis and I in axis
* Find the gradient
* Gradient = Resistance
 
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they have said the resistance of each lamp is 8.0 and that it has increased by 15 %
thus the resistance of each lamp is
=8*15/100
=8.4

they have said that that if the current is 0.9 A then the fuse will flow
thus the resistance in the circuit should be
240/0.9
=266.7

if each lamp gives a resistance of 8.4 A, then the required no. of bulbs to equal the resistance is
266.7/8.4
=31.7

40-32
=8 lamps should fail
 
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they have said the resistance of each lamp is 8.0 and that it has increased by 15 %
thus the resistance of each lamp is
=8*15/100
=8.4

they have said that that if the current is 0.9 A then the fuse will flow
thus the resistance in the circuit should be
240/0.9
=266.7

if each lamp gives a resistance of 8.4 A, then the required no. of bulbs to equal the resistance is
266.7/8.4
=31.7

40-32
=8 lamps should fail
Jazakallahu Khairan.
 
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