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here you go.....
PART(D)
the two masses we chose were 600g and 400g, both of them are acting downwards
first we convert these to newtons, but for that they must be in kg so 600g=0.6kg and 400g=0.4kg
we multiply both by 10 to get their weights (forces) 0.6kg=6N and 0.4kg=4N, so until now we have a total of 10N force acting downwards but we know that the disc also has a mass which is 200g=0.2kg=2N, therefore now the downward forces are equal to 12N,
Thus we know that 12N is the force acting on the pivot![]()
Thanks alot!!!!........You r really good at physics!!there is no need to mention anything about upward forces = downward forces because the asked about force acting ON the pivot not force EXERTED by the pivot