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Physics P5 All Info You Need !!

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and i am almost ready to blast the test tomorrow and i need help with aparatus!
please someone post the list of aparatus we are going to need like what should i use to measure the velocity of wind?
what should i use to measure magnetic flux density? and so on!
please please!
i need the list of apartus! and please reply fast! :) because test is really knocking at the door!
 
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Untitled_design.png
mic is supose to be out
its a question from w 03 or 04
 
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how to draw the error bar when the errors are in the x-axis???are they sideways??? also,how to draw the worst acceptable line then??is it from the extreme right (highest) of the first point to the extreme left of the last point???plz reply anyone..ASAP..plzz help..!!

error bars in x axis are horizontal...worst acceptable line Should pass from left of top error bar to right
of bottom error bar or right of top error bar to
left of bottom error bar
 
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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_51.pdf
Q2 (b) When t=time for 10 osc. T=time for one.
So for eg:t=19.6 (+-) 0.2 So in order to find T we divide 19.6/10, do we even divide the error also by 10 ? o_O
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_51.pdf
Q1- How do we increase the speed? Guide me with this exp.
SalmanslK PLease Please.



for question 1

( log(19.8)-log(19.6) )*(log(19.6))= 5.69*10^-3 -------> 0.005 or 0.006 :)


question2:
(omega)w= angular speed/time taken

for one complete rotation measure time taken(T) and hence; w= 2(pie)/T
 
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for question 1

( log(19.8)-log(19.6) )*(log(19.6))= 5.69*10^-3 -------> 0.005 or 0.006 :)


question2:
(omega)w= angular speed/time taken

for one complete rotation measure time taken(T) and hence; w= 2(pie)/T

for question 1
log 1.98 - log 1.96
it was the idea suggested by a brother.but i m also confused.
 
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can anyone tell me how to connect cro and signal generator to a circuit with diagram?
 
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GUYS you can get the uncertainty both by subtracting log of mean from log of max OR subtracting log of minimum from log of max and dividing by 2!
 
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