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Physics Paper 1 2011 Discussion Thread

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the answer for this graph is B..jus think urself..R=rho*l/A...and rho is increasing so does l...whereas A is constant..so R is increasing...and I is same there..so Voltage needs to decrease....now jus put the value urself....jus for 1st keep rho and l=1 urself....for 2nd keep 2rho and l=2..do similarly...and judge how its decreasing..!! this is the way u do..this is for easy!!
 
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0.5fx gives u strain energy..but where u draw it to scale..the line that forms traingle is below that curve..so u shud use ur sense that it must b greater than 0.10J...therefore 0.11J..!!
 
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Ash1994 said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s10_qp_12.pdf

Q 5 and 9 please!
8.5 square wave=60ms
or 1 Sw=60/8.5=7.058ms....therefore 7.058*10^-3 seconn...so frequency=1/t= 10^3/7.058=141. 66=140


for 9..its very difficult to reach a answer..but the thing is...gradient of velocity time graph gives acceleration..but while drawing line..jus take the line upto which its straight..!! so identify straight line..and calculate the answer...by y2-y1/x2-x1
 
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Thanks . .for the first time somebody solved my question in a Thread!
Now. .solve this please
12 Forces of 3 N, 4 N and 5 N act at one point on an object. The angles at which the forces act can
vary.
What is the value of the minimum resultant force of these forces?
A 0
B between 0 and 2 N
C 2 N
D between 2 N and 4 N
 
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Again @ deathdealer... the answer is C, since the temperature is constant, at 0 degrees, so they both have the same kinetic energy ;) that easy :)
 
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Ash1994 said:
Thanks . .for the first time somebody solved my question in a Thread!
Now. .solve this please
12 Forces of 3 N, 4 N and 5 N act at one point on an object. The angles at which the forces act can
vary.
What is the value of the minimum resultant force of these forces?
A 0
B between 0 and 2 N
C 2 N
D between 2 N and 4 N
the resultant of 4N and 3N is 5N..and the Remaining 5N force can be applied in the opposite diretion to the Resultant fo 4N and 3 N..making the total net force 0N. so the answer is A
 
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every one wire has 0.005 resistance.
Resistance for 800 m for each wire = 800 x 0.005 = 4

total R = 8 ohm
cuz there are two wires

V = IR = 8 x 0.6 = 4.8

total V = 16+4.8= 20.8
so minimum V is C ..
 
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