physics paper 42 expected gt and discussion

[Distillator]

What was the answer to astronaut one and the one which asked why momentum is not same?

There must have been a third particle involved or released in the collison.

 

[happyperson]

There must have been a third particle involved or released in the collison.

Astronaut one?

 

[Distillator]

Astronaut one?

oh my bad i was referring to the Xray Photon and electron one. what was the astronaut again?

 

[happyperson]

oh my bad i was referring to the Xray Photon and electron one. what was the astronaut again?

It was that what did the astronaut meant when he said he was 'weightless' ?

 

[Princess Raven]

Wasn't mass 430 and the ke the amplitude was 3 and 0.9 so how did u get 0.32

Mass was 130g. and KE ratio was around 0.32

 

[happyperson]

Wasn't mass 430 and the ke the amplitude was 3 and 0.9 so how did u get 0.32

Amplitudes were 3 and 1.7.

 

[Distillator]

Wasn't mass 430 and the ke the amplitude was 3 and 0.9 so how did u get 0.32

Amplitude was 3 and 1.7?

 

[Princess Raven]

Amplitude was 3 and 1.7?

Really.. K maybe I read wrong... But still it's it gonna be 3.1 then coz ( 3*10^-2)^2/(1.7*10^-2)^2

 

[Distillator]

Really.. K maybe I read wrong... But still it's it gonna be 3.1 then coz ( 3*10^-2)^2/(1.7*10^-2)^2

Wasnt it the other way round? the fraction?

 

[Distillator]

It was that what did the astronaut meant when he said he was 'weightless' ?

Oh most of his weight is converted to centripetal force to make him go in a orbit around the earth and very small forces holds him to the surface

 

[hamzashariq]

Wasn't mass 430 and the ke the amplitude was 3 and 0.9 so how did u get 0.32

Mass was 430g. people who forgot to take the efficiency into account got 130. (I did too, but later i realized and corrected it.)

 

[Ahmed Aqdam]

Mass was 430g. people who forgot to take the efficiency into account got 130. (I did too, but later i realized and corrected it.)

Yes, mass was 430g. Anyone got the answer for the last part for the number of years?

 

[Distillator]

Mass was 430g. people who forgot to take the efficiency into account got 130. (I did too, but later i realized and corrected it.)

Took efficiency into account . dead sure it was 130g. When you used the answer we previously calculated for number of alpha particles per second we use that as Activity. and when we use that as activity efficiency was considered. Use formula A=TN and then etc.

 

[Princess Raven]

Yes, mass was 430g. Anyone got the answer for the last part for the number of years?

3.52 years I guess, where did u gut put M on the graph? And was the pd 6mf

 

[Ahmed Aqdam]

3.52 years I guess, where did u gut put M on the graph? And was the pd 6mf

M at the top right, not sure if that is correct. And pd was 6mV.

 

[Princess Raven]

Took efficiency into account . dead sure it was 130g. When you used the answer we previously calculated for number of alpha particles per second we use that as Activity. and when we use that as activity efficiency was considered. Use formula A=TN and then etc.

Yeah that's what I did too.. But I got 430?

 

[Princess Raven]

Lol okay lost that too I put it on the top left where x=0

M at the top right, not sure if that is correct. And pd was 6mV.[/QUOTE

 

[Distillator]

Yeah that's what I did too.. But I got 430?

how did you calculate the decay constant?

 

[Princess Raven]

how did you calculate the decay constant?

Ln(2)/half life but u have to change the half life from years to seconds

 

[Ahmed Aqdam]

Lol okay lost that too I put it on the top left where x=0

How did you find the velocity? V*q/m=1/2v^2, right?

how did you calculate the decay constant?

ln 2/(2.8*365*24*3600)