Physics Paper 6 help needed :(

[lavanyamane]

http://www.xtremepapers.me/CIE/Cambridg ... _qp_63.pdf
Q.3 (c)
Can someone please help me with this question? I just don't seem to understand how to solve it!

 

[basimnazir]

Well, whats hard in it? Look it's really easy, we will go step by step

3.c.i. Use the formula R= V/I and find the resistance. Like so:
For the first row... 2.2/0.36= 6.1 Ohms and the next row 4.1/0.68=6.03 Ohms (2 decimal places) and so on....

ii. As follows:
V/V I/Amps or A R/Ω

iii. Yes
The value of R is constant because the R for first row is 6.1 and for the second row its 6.03, they are approximately the same.

Hope this helps, I have an exam too, tom. We will ace it! If you don't understand don't hesitate to ask!

 

[lavanyamane]

Sorry! Wrong paper..
http://www.xtremepapers.me/CIE/Cambridg ... _qp_61.pdf
This is the one, Q. 3 (c)
Hope you can help me

 

[cheesww]

Heres the answer...hope yu find it helpful:
The Theory suggests that current will b HALF(0.5) yur answer to (a) therefore:
0.5 * 0.3= 0.15
and from the table the current 0.15 gave 10.1 ohms
so 10.1 is yur answer

 

[basimnazir]

Look the theory suggest that the current is 1/2 so multiply your above (a) answer with 1/2 so...
1/2 x 0..3 = 0.15
In the table it says 0.15 give 10.1 Ω so 10.1 is the answer correct it to 2 significant figures so 10 Ω...which is same in the mark scheme

 

[basimnazir]

lol chesybite said it!

 

[lavanyamane]

AH! I thought it has to be 0.5 A ! Thanks guys !

 

[basimnazir]

You're most very welcome!

 

[KareemXPF]

Haha... That question is confusing alot..
i asked the teacher about it.. it is what is said above
the answer is 10.1 ohms..
As 0.5i = 0.15 Amps
Look at the table ... 0.15 A = 10.1 Ohms
Good luck guys
Just pray .. and you must have a feeling that allah will help you

 

[lavanyamane]

http://www.xtremepapers.me/CIE/Cambridg ... 9_qp_6.pdf
Q. (a) (iii)
Can you awesome people please help me?

 

[lavanyamane]

Q. 1. (a)(iii)

 

[haochen]

just drw a block of wood on each side of the tube.
and draw a ruler on top of the block and tube.
it is harder to explain than demonstrate

hope u got it

 

[KareemXPF]

Sorry but your answer isnt correct.
Put one block up
and one down
and put the ruler by the side and measure

 

[lavanyamane]

Yeah I figured it out just 5 mins ago
Thank you!

 

[KareemXPF]

Your welcome

 

[lavanyamane]

http://www.xtremepapers.me/CIE/Cambridg ... 7_qp_6.pdf
Q. 1 (c) guys?

 

[unplugged]

http://www.xtremepapers.me/CIE/Cambridge%20IGCSE/0625%20-%20Physics/0625_w07_qp_6.pdf
Q. 1 (c) guys?

The findings support this. The rate of cooling was lower in the last minute than in the first minute indicating that the current temperature effects the rate.

1. the room temperature
2. the volume of the water
3. The beaker used

 

[haochen]

Sorry but your answer isnt correct.
Put one block up
and one down
and put the ruler by the side and measure

ohh my bad
i thought u wanna measure the width

 

[lavanyamane]

http://www.xtremepapers.me/CIE/Cambridg ... 5_qp_6.pdf
Q. 1. (c). In the mark scheme for this paper, what does CIE mean by 'dead space'?

 

[lavanyamane]

http://www.xtremepapers.me/CIE/Cambridg ... 8_qp_6.pdf
And in Q.2(a) here, do we draw the diagram with one end of the voltmeter and one end of the resistor not connected? We draw an incomplete circuit?