Physics Unit 4 JUNE 11/6/12

[Evolution]

e=c^2 x m
so e= (3x108)^2 x (238 x 1.0073 u)
Tell me if it's the right answer or not.

 

[svenas]

e=c^2 x m
so e= (3x108)^2 x (238 x 1.0073 u)
Tell me if it's the right answer or not.

The ans was 1800 Mev ufff im getting crazy even time constant frm graphs im nt able to solve nw

 

[étudiante]

Hii plz if u can solve 4 me this que . Thanks in advance
(ii) Calculate the theoretical energy released when a U nucleus is formed from individual protons and neutrons. Give your answer in MeV.

Data (masses):

U = 238.0003 u ,proton = 1.0073 u, neutron = 1.0087 u

Uranium 235 or 238?

 

[svenas]

Uranium 235 or 238?

238

 

[étudiante]

Hii plz if u can solve 4 me this que . Thanks in advance
(ii) Calculate the theoretical energy released when a U nucleus is formed from individual protons and neutrons. Give your answer in MeV.

Data (masses):

U = 238.0003 u ,proton = 1.0073 u, neutron = 1.0087 u

m before formation = 92 * 1.0073 + 146 * 1.0087
m after formation = 238.003
change in mass = 1.9388
use dis in e = mc2

 

[svenas]

m before formation = 92 * 1.0073 + 146 * 1.0087
m after formation = 238.003
change in mass = 1.9388
use dis in e = mc2

how did u get the ans?i didn understand it

 

[étudiante]

how did u get the ans?i didn understand it

U need to find the initial mass... do dat by finding the mass of 92 protons and 146 neutrons individually (dese will be requred to make the uranium atom) and subtract dat mass from the actual mass of the Uranium nucleus given... this gives a change in mass n use dis value as "m" in e = mc2

 

[svenas]

U need to find the initial mass... do dat by finding the mass of 92 protons and 146 neutrons individually (dese will be requred to make the uranium atom) and subtract dat mass from the actual mass of the Uranium nucleus given... this gives a change in mass n use dis value as "m" in e = mc2

thnx alot actually im nt well prepared alot of question i wasn't able to solve ok if u don mind i hve a que Q 18 part (e)

 

[étudiante]

thnx alot actually im nt well prepared alot of question i wasn't able to solve ok if u don mind i hve a que Q 18 part (e)

ur welcome n sure...

just a sec

 

[étudiante]

is the answer out of the paper?

 

[svenas]

is the answer out of the paper?

yes bt how did u get it?

 

[Evolution]

thnx alot actually im nt well prepared alot of question i wasn't able to solve ok if u don mind i hve a que Q 18 part (e)

there is no part e

 

[svenas]

there is no part e

there is 4 the direction of the magnetic field

 

[étudiante]

yes bt how did u get it?

point ur second finger in the direction of proton movement and u'll see that ur thubb point putwards if its to be perpendicular to it

 

[étudiante]

there is no part e

LOLZzz.. i missed it too at first the one where we have to choose one direction from the three given

 

[svenas]

point ur second finger in the direction of proton movement and u'll see that ur thubb point putwards if its to be perpendicular to it

ya bt im getting my second finger into the page

 

[svenas]

LOLZzz.. i missed it too at first the one where we have to choose one direction from the three given

the papers r jst stupid im regretting for taking an A level

 

[Evolution]

ohh u mean question 17 part e. yah u use the right hand rule. thumb for motion, index for field, and middle for emf

 

[svenas]

ohh u mean question 17 part e. yah u use the right hand rule. thumb for motion, index for field, and middle for emf

ohh ok bt when to use the right hand rule?

 

[Evolution]

when you have any of these things given, if you know where the emf, or motion, or field is, then use it. The left hand rule is force for the thumb, field for the index, and current for the middle.