• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

physixs ideal gas question

Messages
2,619
Reaction score
293
Points
93
wat anser u get for ii....i m getting 746 bt markschemes says 741
 

Attachments

  • xf.PNG
    xf.PNG
    45.4 KB · Views: 94
Messages
2,619
Reaction score
293
Points
93
the approach i used was that 1st u get 415 moles of gas in cylinder in part i ans......then using info in sceond line u cn figure out no . of mol in one baloon....theyturned out to be .55 mol.....
so 1 baloon has .55 mol ....how many baloons will have 415 moles....so by this way u get 746 .....is there anything rong i did
 
Messages
1,594
Reaction score
483
Points
93
I get 746 for part (ii) as well.
P1V1 = P2V2
=> V2 = (2.50 x 10^7 x 4 x 10^4)/ (1.85 x 10^5)
=> V2 = 5.405 x 10^6
No. of balloons that can be filled = Total volume of hydrogen gas/ Volume in each balloon
= (5.405 x 10^6)/ (7.24 x 10^3)
= 746.603
So 746 balloons can be filled. Same answer this way, too.
 
Top