Post all of ur doubts here Mishi :)

[mehria]

Hadia is que me mujy bi samaj nhi aya k A pe current q zero hai or ciii part samaj nhi aya :-/

yr agar hum contact C ko A pe attach karay to wese be current zero ho hoga... cuz A pe resistance zero hai

 

[mehria]

Hahaha ok here comes da 1st one

for part b (i) use the principle of momentum n u'll get ur ans...
i.e. initial momentum=final momentum
as initially they r stationary so initial momentum will be zero...
so :- 0= 2400X - 800x
2400X=800x
x/X=2400/800= 3.0

b (ii) we knw that loss in strain energy is equal to gain in kinetic energy
n 0.49 J is the strain energy on both of the springs so we will consider the kinetic energy of both of the springs :

the velocity for 2400g mass is 1/3v
so
0.49=[ 1/2 x 2.4 x (1/3v)^3)] + (0.8v^2/2)
solve it n u'll get ur ans

 

[mehria]

Ye hai us ka part a nd b

yr ye question meine n shazia ne dono solve kiya tha but hmein ye samajh nhi ayi k wo 0.045 phr se q subtract kr rahay hai :/

 

[Mashal zeb]

To phir is ka kya karen

 

[Mashal zeb]

yr agar hum contact C ko A pe attach karay to wese be current zero ho hoga... cuz A pe resistance zero hai

Or part ciii b

 

[Mashal zeb]

Or ye bbb

 

[Mashal zeb]

Ye polarisation wale que ka pehla part mujy polarisatio or uski samaj nhi aye part c me

 

[mehria]

To phir is ka kya karen

idk...cum on monday..phr discuss karenge

 

[mehria]

Or part ciii b

ye mjy b cnfuse kr rhi hai...

 

[mehria]

Ye polarisation wale que ka pehla part mujy polarisatio or uski samaj nhi aye part c me

iska part c to hai hi nhi

 

[Mashal zeb]

iska part c to hai hi nhi

Is ka part c

 

[mehria]

Is ka part c

p will not chnge its position as it is in the mid point.... where as X n Y will chnge their position..check the attachement
Note that it is rotating at an angle of 90 degrees

 

[mehria]

Mashal zeb

 

[Mashal zeb]

Ths question

 

[Mashal zeb]

Q13 nd 14

 

[Thought blocker]

Ths question

Ok..This is Tricky But involves Math Skills..!!
Look Proton Has Charge of (+)1.! We need to end Up at One Using Values of Up quark and Down Quark.!

If U Take 2 UpQuarks = (+)(2/3) * 2 = (+)(4/3)
And One Down Quark = (-)(1/3) * 1 = (-)(1/3)
When You add them Together..
(+)(4/3) + (-)(1/3)= (+)1

 

[Thought blocker]

Q13 nd 14

13)
5*2 is upwards and so is 10*2
while 20*3 is down wards
60-30=30 A

14)

 

[Mashal zeb]

Ok..This is Tricky But involves Math Skills..!!
Look Proton Has Charge of (+)1.! We need to end Up at One Using Values of Up quark and Down Quark.!

If U Take 2 UpQuarks = (+)(2/3) * 2 = (+)(4/3)
And One Down Quark = (-)(1/3) * 1 = (-)(1/3)
When You add them Together..
(+)(4/3) + (-)(1/3)= (+)1

Ths z so hard i stil did nt get it

 

[Thought blocker]

Ths z so hard i stil did nt get it

According to syllabus, we must know that a proton has a charge +e (the basic/elementary charge)

Now according to this question, protons themselves are made up of particles called quarks. There are different types of quarks, each one with its own charge.

Whatever the combination of quarks, the total charge on a proton must be +e. Hence the sum of the charges of all the constituent quarks in a proton must be + e.

So simply check the sum of charges of each option to see if it is +e.

option A: 3 x (-e/3) = -e
option B: (2e/3) + (-e/3) = +(e/3)
option C: (2e/3) + 2(-e/3) = o
option D: 2(2e/3) + (-e/3) = +(3e/3) = +e

answer is D

 

[Mashal zeb]

Ok ok i got it u mean v have to take thez stupid quarks to getva value equal to 1 becuz proton has +1 charge?