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Probability ....last part not clear.?

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One turn of a game is as follows. Two coins are tossed. If the exposed faces of the two coins are the same as each other, then BOTH are tossed for a second time and the turn ends. Otherwise, the turn ends after the first toss of the coin. The scores, X obtained in the turn, is equal to the total number of HEADS exposed during that turn.

(i) I have already constructed the prob. distribution of X. P(X=3)=1/8 and P(X=1)=5/8.
(ii) Already calculated. E(X)=1.5 Var(X)=1
(iii) The scores obtained two randomly chosen turns are X1 and X2. E(X1 - X2)=0. PLEASE HELP ME IN FINDING OUT P(X1=X2).
 
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