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Riddles

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The classic.

3 guys on a journey decide to spend the rest of the night in a hotel nearby. For the night stay, the hotel manager charges them $300. The three guys pay $100 each. Later on, the hotel manager realizes he made a mistake and that the bill totalled to $250. He asked a worker to give the $50 back. The greedy worker pocketed $20 and gave each of the three guys $10.

Since the guys originally paid $100 each and now get $10 back, they paid $270 in total. The worker had $20. Where is the remaining $10?
Since the guys originally paid $100 each and now get $10 each back, they paid $280 in total, right?
 
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From $50, the worker pockets $20, so gives back $30 back to the 3 guys.
So, they've shelled $300 minus $20.

= $280

Well, well, well, whatever. Idk.
He gives $30 back, so why are you subtracting $2o from $300??

And they are?
Well the 3 guys already had it.
Considering $250 (acutal price), they each should have paid $83.333, but they paid $90.
So practically they already had the $10
 
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He gives $30 back, so why are you subtracting $2o from $300??


Well the 3 guys already had it.
Considering $250 (acutal price), they each should have paid $83.333, but they paid $90.
So practically they already had the $10

You got it. Altogether they paid $250 (i.e. 83 1/3 each). Then each had another $10 which took it to $280 total and the remaining $20 is with the clerk.

The $10 is nowhere, you just are calculating it wrong. :p
 
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For those who don't get it, the three guys paid $270 in total and got $30 back in total. The worker's $20 comes in that $270, you don't add it again.

So if you remove the worker's $20 from the $270. It leaves $250 which goes to the hotel, the $20 to the worker and the $30 to the 3 guys.
 
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I am just pointing a flaw. Speed breakers don't exist abroad coz people actually stop of all things on a stop sign.
 
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