sat 1

[Anum96]

 

[***amd***]

View attachment 58903

1
because gradient (m) of any line perpendicular to a line with m = x is '-1/x' (-ve reciprocal)
u have 4 lines, opp two parallel to each other and other 2 perp to them.
lets take gradient of any 2 opp lines as x
gradient of the other 2 lines = -1/x

product of all 4 gradients = x * x * -1/x * -1/x = 1

 

[Anum96]

1
because gradient (m) of any line perpendicular to a line with m = x is '-1/x' (-ve reciprocal)
u have 4 lines, opp two parallel to each other and other 2 perp to them.
lets take gradient of any 2 opp lines as x
gradient of the other 2 lines = -1/x

product of all 4 gradients = x * x * -1/x * -1/x = 1

Thank you!