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Thank you so much!if you have ANY +ve integer k, doesnt matter if it is odd or even, the value '2k' is always even.
since 2k is even, 2k+1 is odd.
any product of an odd and an even number is even.
so 2*odd = even
2(2k + 1) = even i.e. double the odd number = 4k + 2