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how was the last question guys :O ? of the distrubution table ?
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and what if the person writes the ans in 3 sf ???
hey frens in the question of permutation and combination do we need to consider the trees (eg: all hibiscus) as identical ones.....what are your answers for this question????
Can any one here tell me why u cnt do
2C2*4C2*9C2*9C6
In quest 6 part i ???? :'(
Can any one here tell me why u cnt do
2C2*4C2*9C2*9C6
In quest 6 part i ???? :'(
I did the same
I am nt sayng to justify ur ans. I am askng why my method is wrng?No, there were to be 3 such options made. 2 was the least it had to be and the total was 12. There were three groups so it (2C2*4C2*9C8)+(2C2*4C3*9C7) +(2C2*4C4*9C6)
I am nt sayng to justify ur ans. I am askng why my method is wrng?
Sory still no !Right there in the answer is the reason. Its like you need to chose 12 out of these and there must be atleast 2 of all three kinds, to begin with take 2 of the 2 of oen kind, 2 of the four of the other and to make it twelve 8 of the 9 of the third batch i.e. 2C2*4C2*9C8. Moving on you can make other options but not getting any lower than 2 of each type so 2C2*4C3*9C7 Now you cant have more than 4 of the second batch so third and last option 2C2*4C4*9C6 There have to be atleast 2 of each so you consider all options above atleast 2 in each batch. Hope you get it now
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