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Statistics P62 3rd Nov

R

RatJumper

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Guys for stats question 7 part iii this was the question and my answer to it. did u guys get the same?

The info they gave was:
If there are 10 men and 9 women. What are the ways of choosing 6 people if there are atleast 4 men and 1 woman.

iii) If one particular man or one particular women are on the committee but not both.

Answer I got:

(9C3*8C1*13C1) + (9C3*8C2) + (9C4*8C1) + (8C1*9C4) + (8C0*9C5) = 13230
 
S

sparkie

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Well I did it with different way
That means 4 different situations
Tracey is girl and I forgot the mans name. Anyway I will call him M
G1=M 9x8x7x6x8 24192
G2=M 9x8x7x8x7 28224
G3=T 9x8x7x6x5 15120
G4=T 9x8x7x6x8 24192
add them up
91728
or something like that
It's defo not as low as 13k
 
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