Statistics S1 Doubts

[ahmadumar]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_62.pdf
Q4(i) Why is the answer '45-50' instead of '45-49'? Because the < sign does not have equal sign
Q4(iv) Shouldn't we use Class boundaries in x-axis to draw the graph?
Mark scheme: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_62.pdf

for the first part what u wrote will gain marks. and for the forth part u r supposed to do just as in the mark scheme. I dont get what other way u trying to say

 

[B!(+)(+)dy $k(_)!!]

Albumin Please solve these doubts...

 

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Albumin 5. ii)

 

[B!(+)(+)dy $k(_)!!]

Albumin 7 (ii) (b)

 

[abdul moeed rana]

Albumin 5. ii)
View attachment 48584

1.245 standard deviation above the mean,????mean fiven 82 and s.d given 3.2
34 s.d within the mean,mean 42, s.d lets say 4.given
how will we solve this.

 

[B!(+)(+)dy $k(_)!!]

1.245 standard deviation above the mean,????mean fiven 82 and s.d given 3.2
34 s.d within the mean,mean 42, s.d lets say 4.given
how will we solve this.

How do I understand your FIVEN question?
Kya pucha hai yaar tune..

 

[B!(+)(+)dy $k(_)!!]

Albumin 4 iii and 5 ii)

 

[abdul moeed rana]

How do I understand your FIVEN question?
Kya pucha hai yaar tune..

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_63.pdf
q7 last part
how we know thahttps://www.xtremepapers.com/community/members/121020/y p and q is o.5??

 

[abdul moeed rana]

Albumin 4 iii and 5 ii)
View attachment 48587

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_61.pdf
q3 part 2 and q6 part 4 and 5

 

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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_63.pdf
q7 last part
how we know thay p and q is o.5??

P(X<8.2) = P(Z<0) = 0.5
Therefore, p=0.5 and q=1-p=1-0.5 = 0.5

 

[abdul moeed rana]

P(X<8.2) = P(Z<0) = 0.5
Therefore, p=0.5 and q=1-p=1-0.5 = 0.5

please elaborate,p<10 is given ,not p<8,2,so we'll consider p<8,2 as p<0??

 

[abdul moeed rana]

P(X<8.2) = P(Z<0) = 0.5
Therefore, p=0.5 and q=1-p=1-0.5 = 0.5

a general thing,how do we calculate p(A and B) to prove p(A) and P(B),when p(a) and (B) is given

 

[abdul moeed rana]

P(X<8.2) = P(Z<0) = 0.5
Therefore, p=0.5 and q=1-p=1-0.5 = 0.5

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_61.pdf
q3 all

 

[abdul moeed rana]

P(X<8.2) = P(Z<0) = 0.5
Therefore, p=0.5 and q=1-p=1-0.5 = 0.5

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_63.pdf
q3 all

 

[abdul moeed rana]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_61.pdf
q5 plzz,
within 12 gof mean means???

 

[Albumin]

Albumin Please solve these doubts...
View attachment 48583

 

[Albumin]

Albumin 5. ii)
View attachment 48584

 

[Albumin]

Albumin 7 (ii) (b)
View attachment 48585

To be honest best way is to make list off all possible outcomes

 

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P(R intersection S) = 1/6
Howwww?
And how P(S) = 0.4
I'm confused?

 

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But they said on one of every four next days ?
So why P(X=4) instead it shud be P(X=1) naa?