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I am able to understand the concept but the simplification is hard. Please help me tomorrow is my paper.
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Stuck in question 1 November 2009 p1 mathematics(9709)
- Thread starter dany5017
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link?
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sweet and simple..
1)integrate dy/dx
2)use co-ordinates to find y-intercept (that is c)
3)construct the final equation
1)integrate dy/dx
2)use co-ordinates to find y-intercept (that is c)
3)construct the final equation
- Messages
- 144
- Reaction score
- 107
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- 53
1)If u wanna integrate
3(x)-1/2 - x
3(x)1/2 / 1/2 - x2/2 = 6(x)^1/2 - x^2 / 2 => y = 6(x)^1/2 - x^2 / 2 + c 2) input x and y calculate c and form equation ...
3(x)-1/2 - x
3(x)1/2 / 1/2 - x2/2 = 6(x)^1/2 - x^2 / 2 => y = 6(x)^1/2 - x^2 / 2 + c 2) input x and y calculate c and form equation ...