Thinking Skills Quetsion

[whatsmyname]

the question comes first, followed by my crude solution which doesn't admittedly show strong thinking but does the job. what i dont understand is the yellow underlined parts. why does it say that we have to add the full lenght of the end link and why does it subract 1.2 exactly and then add 1 to the fraction later on? im finding this issue rather confusing so any help would be appreciated..

 

[destined007]

This is what I get from this:
1.2 is actually the length of the end spring. You don't want to take that length into account because it's one side is always exposed. You only take into account those links that are attched to both ends, ie, the middle links. So you subtract the length of end link, calculate the number of middle links and add 1 end link to it.

 

[whatsmyname]

hey i still dont understand, and i believe your explanation is flawed. I think by end spring you mean to say the "tongs or clips" that are used to fix/close the necklace into place rite, like a lock kinda thing? if u mean that then the question says that the necklace is broken in such a way that the 2 pieces each feature one of the closing fittings, and the +1 to the fraction IS the additional length of the closing fitting which is indeed part of the length of the necklace because while it may be a clip it is also a kind of link.

and so my question abt the +1 is clarified, but my question about WHY THE -1.2 to 33.2 and 25.2 is NOT. Those lengths are subtracted, but I fail to understand why, and any FURTHER help would be appreciated..ive exhausted my thinking over this one. thanks

PS - for some1 asking for thanks on his sig u seem to have pretty few thanks sent out compared to having in, so either ur a god of helping or u dont thank others much lol

 

[destined007]

Here:


PS. i have been helped 3 times in my entire forum posts and i have thanked them every time.

 

[whatsmyname]

wow that figure was explanatory..thank you for the explanation...and ya gotta agree ur a helping god here..pressing thanks again..

 

[whatsmyname]

ok bro im back with more questions to pester you - and anyone else thats intrested. these are from the Thinking Skills 8436 P1 summer 2004:

and

and these are from collegeboard SAT, but since they also require reasoning i think ur the man:

the correct answers are in the red square, and i require some logical explanations for them since my brain has failed me on these...thanks in advance

 

[destined007]

 

[destined007]

polygon one requires time.

 

[whatsmyname]

thanks a lot bro...solved the polygon one btw and this is how its done:

the covered up figure forms for us a QUADRILATERAL - so sum of all angles is 360 and so the unlabeled angles each measure (360-80)/2=280/2=140 {figure is equilateral}
Now formula for total of internal angles is (n-2)x180 where n is the no of sides.
So, (n-2)x180= 140 x n AND n = 9.

 

[whatsmyname]

however, you might want to work on this one then in the meantime:

something gives me a hunch these questions will keep rolling in..so sorry for any inconvenience caused thanks in advance man..ur gr8

 

[destined007]

however, you might want to work on this one then in the meantime:

something gives me a hunch these questions will keep rolling in..so sorry for any inconvenience caused thanks in advance man..ur gr8

 

[whatsmyname]

thanks man..really helped..but i had realized this one b4 the SAT..which went pretty well anyway...ur a great person

 

[whatsmyname]

ok bro couple of more brain teasers..but these should be easy for you..hope you dont mind but im selfstudy so no school help or anything..
BUT before that i had meant to ask you but forgotten, in your answer explanation for q19 above abt the trains why does 730 to 2030 have 795 mins in between? 13hrs=780 mins am i rite?

MAJOR HELP REQUIRED PLEASE GIVE FIRST PRIORITY TO THESE:

______________________________________________________________________
IF YOU HAVE MORE TIME:

thanks in advance

 

[ryandigweed]

any help..

 

[ryandigweed]

Answer E.. but need calculations

 

[whatsmyname]

Answer E.. but need calculations

This question is about setting up a model. Let us begin by calculating at what time the model begins: [We use the formula distance = (speed x time), abv d=st]

Model begins when R leaves P. R covers 30 km to P in t=d/s = 30/40 = .75 hrs = 45 mins. Then, @P he takes a 15 min break, which make his start time at the model 1 hour from 12 o'clock=1 o'clock.
In the meantime, leaving P@ 10 and till 1, b has traveled d=st = 20x3=60km.

Now, set the model up, based on the fact that you want the diff of distance to be 20 km as - Dr - D b =20km
We know that, Dr = st = 40t & Db = st+60 = 40t+60 [The 60 km is the one he covers since leaving P, and st stands for the distance he covers after the model starts]
Finally, Dr - Db = 20 or 40t - 20t - 60 = 20 and HENCE t = 80/20= 4 hours.
Now, 1:00 +4 hrs= 5 o'clock or 17:00 hrs

 

[ryandigweed]

THxxx a million... was stuck on this one since a while...

 

[whatsmyname]

ya no worries..anyhow i hope destined finishes his exam fast enough to answer me before mine, its on coming 24th Oct and like this its gonna be fucked up..ive updated the massive image loaded post above continually if anybody wants to take a look

 

[whatsmyname]

Guys please help - Exam is on 25th October & im a self study student - no school no friends/teachers/tution so only you guys...thanks in advance

 

[ryandigweed]

same here ppr on the 25Oct.. got any last minute tips ?? n wat time is ur paper ???