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Here is a quick equation P1V1 + P2V2 = (total pressure) / (V1 + V2)
This is a disproportion reaction
This is a disproportion reaction
oxidation number of I in HIO is +1, in I2 is 0 and in HIO3 is +5
so HIO to I2 is (+1 -> 0)x2 which is -2 because there is 2 Is in I2.
and HIO to HIO3 is (+1->+5) which is +4
ratio is -2:4 is 1:2 so mol ratio must be 2:1
How 1:2 became 2:1 ??
Thank you sooooooooooooooo much!Here is a quick equation P1V1 + P2V2 = (total pressure) / (V1 + V2)
so new P = (P1V1 + P2V2)/(V1 + V2) = (5x12 + 10x6) /(5+10) = 120/15 = 8
so correct answer is A
C2H5OH + CH3CO2H ->CH3CO2C2H5 + H2O
You are a life saver!!!!!!!!! Thank youuuuC2H5OH + CH3CO2H ->CH3CO2C2H5 + H2O
initial mol 1 1 0 0
equilibrium 1-x 1- x x x
K = 4 = x^2/(1-x)^2
square root both sides
2 = x/(1-x)
2(1-x) = x
2-2x = x
x =2/3
which is B
I think its Bsame doubt here anyone answer plzzz !!
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