URGENT HELP REQUIRED--MATHS

[XPFMember]

Assalamoalaikum!!

Can somebody help me with this question..plz! it's june 2006 P6

 

[princesszahra]

Assalamoalaikum!!

Can somebody help me with this question..plz! it's june 2006 P6

for mean
add all these and then divide by 11 ( donot include 352 as it shows a large deviation hence it is an error)

for mode
the most repeated value
ie 40 in this case

for median
arrange them in ascending order
40 40 41 42 45 47 48 49 50 51 352
so median =(n+1)/2
(11+1)/2
12/2
6
ie 6th term =47
hope u get it

 

[XPFMember]

Assalamoalaikum!!

what abt the explanation...and the thing in the ms i dont get it! http://www.xtremepapers.me/CIE/International A And AS Level/9709 - Mathematics/9709_s06_ms_6.pdf
it's Q:1

 

[WellWIshER]

u canT choose mode AS its not a good measure cuz look at other values they r not around 40
mean is also nout good becuz its affected by an outlier 352 dis value is non-typical(ODD ONE OUT) in da data which increases da over all mean
SO MEDIAN IS DA CORRECT MEASURE

 

[princesszahra]

oops sorry
wellwisher is right in this one!
sorry again!

 

[djdead1]

y wud u need p6now :S

 

[XPFMember]

bcoz i aint appearing for any exams this session!

and well wiser Jazak ALlah Khair
@princesszahra it's ok...no problem

 

[djdead1]

bcoz i aint appearing for any exams this session!

and well wiser Jazak ALlah Khair
@princesszahra it's ok...no problem

o alryttt...luky u al da best wid whtever it is ure askin help fo
!! (Y)