urgent maths paper 4 help needed

[aaaamfa]

plzz ans the question 41/m/j/10: 7a1

 

[Hassan Kazmi]

For A, integrate the first equation v = A (t - 0.05t^2) with respect to t, with boundary t=0 to t=15. Integrating the velocity function gives us the distance, so, equate the integral you just found to 225, as the distance from t=0 to t=15 is 225m.

For B, since v = A (t - 0.05t^2) and v = B/t^2 both when t=15, just equate these two equations using the value of A found as above and t=15.

 

[aaaamfa]

For A, integrate the first equation v = A (t - 0.05t^2) with respect to t, with boundary t=0 to t=15. Integrating the velocity function gives us the distance, so, equate the integral you just found to 225, as the distance from t=0 to t=15 is 225m.

For B, since v = A (t - 0.05t^2) and v = B/t^2 both when t=15, just equate these two equations using the value of A found as above and t=15.

is it the answer for maths 0580/41/m/j/2010 question

 

[Hassan Kazmi]

oops, sorry. I thought it was A level math. Let me get back to you on that.

 

[Hassan Kazmi]

Hm, so I see that 0580/m/j/10: There is no such part as Q7(a)(i).. there is only Q7(a), to which I answer:

First convert the radius of 31cm to m, that is 0.31m. Volume of cylinder is pi*r^2*h = 3.142*0.31*0.31*15 = 4.53 m^3.