Vector discussion...

[Rutzaba]

For a detailed and live vector discussion post your vector doubts here. ^_^
All i need are prayers in return

 

[Rutzaba]

now take out that question of vectors plz... daredevil

 

[Rutzaba]

<a href="http://s1275.photobucket.com/user/Rutzaba/media/Picture1_zps1940f26a.png.html" target="_blank"><img src="http://i1275.photobucket.com/albums/y444/Rutzaba/Picture1_zps1940f26a.png" border="0" alt=" photo Picture1_zps1940f26a.png"/></a>

 

[daredevil]

first question of the thread ^__^

 

[Rutzaba]

View attachment 42541
first question of the thread ^__^

frst diagram samajh aya?

 

[Rutzaba]

View attachment 42541
first question of the thread ^__^

For getting the points of intersection here's wat we do...
step1= convert them into parametric form 1*
step 2= compare x with x of the other line
y with y of the other line
z with z of the other line.
Step 3= we shall have two variables that are given by lambda and sumthing i like to call them t and s
simplifying these equations pick any two
suppose i pick of x and y
Step4 i solve em simultaneously getting a value of s and t
for confirmation il use the third eq of z to verify if or not they do intersect...
once im sure that the third eq is giving me the same value of s and t
il pick up the parametric eq of any one line and put in the value of t if im using line1 and s if using line 2
that shall give us the point of intersection
shall solve it for u after sum tym

 

[daredevil]

View attachment 42541
first question of the thread ^__^

 

[Rutzaba]

<a href="http://s1275.photobucket.com/user/Rutzaba/media/Picture1_zps1940f26a.png.html" target="_blank"><img src="http://i1275.photobucket.com/albums/y444/Rutzaba/Picture1_zps1940f26a.png" border="0" alt=" photo Picture1_zps1940f26a.png"/></a>

View attachment 42541
first question of the thread ^__^

the question i solved u in the math thread... ye uska diagram hai...

 

[Rutzaba]

wait

 

[Rutzaba]

step1= convert them into parametric form 1*
This is a paramtric form...
line 1 (3,-2,1)+t(-1,2,1 )
line 1
x=3-t
y=-2+2t
z=1+t
line 2 (4,4,2) +s(a,b,-1)
x=4+as
y=4+bs
z=2-s

compare x by x
3-t= 4+as
t+as =-1----------eq1
compare y by y
-2+2t=4+bs
2t=6+bs-------eq2

compare z by z
1+t=2-s
t=1-s----------eq3

to eliminate the t factor put eq3 in both eq1 and eq2
putting it in eq1
1-s+as==-1
as-s=-2--------------------eq p
puttingin eq 2
2-2s=6+bs--------eq q
simultaneously solve eq p and eq q

s=-4/(b+2)
s=-2/(a-1)
simplify to get the answer...
2b-4a= -8
b-2a=-4
2a-b=4

 

[daredevil]

Sorry I was late... my internet is giving me a hard time -_-

Yeah I got it from the visual too thanks...

but actually my problem is that i cant seem to figure out how to proceed with the question wen i see it.... i guess i'll go thru my notes once more and then solve as many vector questions as i possibly can.... i'll stay in touch with more questions ^__^

 

[Rutzaba]

Sorry I was late... my internet is giving me a hard time -_-

Yeah I got it from the visual too thanks...

but actually my problem is that i cant seem to figure out how to proceed with the question wen i see it.... i guess i'll go thru my notes once more and then solve as many vector questions as i possibly can.... i'll stay in touch with more questions ^__^

sure

 

[Rutzaba]

u guys make notes in maths?

 

[daredevil]

u guys make notes in maths?

nahi... i got a friend's academy handouts photocopied to help some... u know just in case i forget a point or something..

 

[daredevil]

but i lost those notes >.< cant find them >=0

 

[Rutzaba]

i never made notes actually not in vectors no

 

[Manobilly]

i never made notes actually not in vectors no

I always get confused in what to use where ,ben struggling alot

 

[Rutzaba]

i dun promise but il try to make notes

 

[Manobilly]

i dun promise but il try to make notes

Plz do so,have exams in 6 days .Can we post our doubts and ask you?

 

[daredevil]

For a detailed and live vector discussion post your vector doubts here. ^_^
All i need are prayers in return

I misread this as "For a daredevil..." xD