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Mathematics: Post your doubts here!

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But this has just bounced off the surface, not reaching the bottom...the one in the question first reached the bottom of the tank and then returned back to rise above the water surface
What do you mean it didn't reach the bottom? it did bounce off the bottom of the tank. The one in the question as dropped from a height above the surface of the water and it didn't exceed that height.
 
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Can anyone help please ?My solution is als attached what is my mistake?
 

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Can anyone help please ?My solution is als attached what is my mistake?
Your solution is the answer to the statement 'if ALL china mugs are not together'. That means that 2 can be together but for all separated, the thing which must be taken into account is that not even 2 must be together. For this there is a simple concept which works every time. First see in how many ways plastic cups can be arranged, which is 6! China cups are to be placed in between them so they have 7 possible positions. Hence, their number of arrangements will be 7P3. Therefore the answer will be 6!x7P3
 
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HELP PLEASE IM JUST CONFUSED IN A VERY SMALL PART
upload_2019-4-21_21-21-42.png
So this question is like the last part of a long question and ill summarise things here
There are two parallel lines, one is a tangent to the curve and has the eqn y=0.5x and another lone called AB that intersects the X axis with eqn: (x-1)/2
The question asked to find the perpendicular distance between the parallel lines.
I understood the part it said tan theta =gradient and I got that
I just dont get what does sin have to do with the distance
upload_2019-4-21_21-24-10.png
MARKING SCHEME
upload_2019-4-21_21-24-38.png
 
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HELP PLEASE IM JUST CONFUSED IN A VERY SMALL PART
View attachment 64622
So this question is like the last part of a long question and ill summarise things here
There are two parallel lines, one is a tangent to the curve and has the eqn y=0.5x and another lone called AB that intersects the X axis with eqn: (x-1)/2
The question asked to find the perpendicular distance between the parallel lines.
I understood the part it said tan theta =gradient and I got that
I just dont get what does sin have to do with the distance
View attachment 64623
MARKING SCHEME
View attachment 64624
Capture.PNG

Graph of the two lines, perpendicular distance d and theta the angle of the tangent with the x-axis.

Form the line equation:
tan(theta) = gradient of tangent
tan(theta) = 0.5

You can get sin from tan by:

1. Drawing a triangle where tan(theta) = 0.5, opp side = 1 and adj side = 2
2. Use Pythagoras's theorem for the third side, hypo = root5
3. Calculate sin = opp/hypo

sin(theta) = 1/root5

From the graph:
sin(theta) = d/1
1/root5 = d/1
therefore, d = 1/root5
 
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If any one has done Maths Feb/March 19 Paper 62 then plz match ur answers with me and do tell me where there is a conflict.
1) i) 0.248
ii) 0.362
2) i) 328
ii) 58.2
3) i) 0.252
ii) 145
4) i) 1/15
ii) 2.33 and 1.16
5) ii) 72kg and 15kg
6) i) 0.117
ii) 3
iii) 0.173
7) i) 30240
ii) 360
iii) 5880
iv) 4
v) 16
 
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If any one has done Maths Feb/March 19 Paper 62 then plz match ur answers with me and do tell me where there is a conflict.
1) i) 0.248
ii) 0.362
2) i) 328
ii) 58.2
3) i) 0.252
ii) 145
4) i) 1/15
ii) 2.33 and 1.16
5) ii) 72kg and 15kg
6) i) 0.117
ii) 3
iii) 0.173
7) i) 30240
ii) 360
iii) 5880
iv) 4
v) 16

Same except:

3(ii) 135
K has to be smaller than the mean(140) for the probability of being greater than it to be more than 0.5(0.675)

6(ii) 7
Prob(atleast one) = 1 - Prob(none)
1 - 0.65^n > 0.95
solving for n gives me 7
 
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View attachment 64627

Graph of the two lines, perpendicular distance d and theta the angle of the tangent with the x-axis.

Form the line equation:
tan(theta) = gradient of tangent
tan(theta) = 0.5

You can get sin from tan by:

1. Drawing a triangle where tan(theta) = 0.5, opp side = 1 and adj side = 2
2. Use Pythagoras's theorem for the third side, hypo = root5
3. Calculate sin = opp/hypo

sin(theta) = 1/root5

From the graph:
sin(theta) = d/1
1/root5 = d/1
therefore, d = 1/root5
Ahhh thanks
Its harder when you have to visualise it :')
 
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Same except:

3(ii) 135
K has to be smaller than the mean(140) for the probability of being greater than it be more than 0.5(0.675)

6(ii) 7
Prob(atleast one) = 1 - Prob(none)
1 - 0.65^n > 0.95
solving for n gives me 7
Alright thanks! I've spotted my mistakes:unsure:
 
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Alright thanks! I've spotted my mistakes:unsure:
You have your p3 answers?

Mine:
1
(ii)12.2
2
(ii)4^(1/5)
3
(i)tan = (2root2 - 1)/(1 - root6)
(ii)128.4, 308.4
6
y = e^(x/2)
7
(a)1 - i and 20/8 + (4/8)i
8
(i)2- 4/(2+x) + 6/(3-2x)
(ii)2 + (7/3)x + (7/18)x^2
9
(i)56.9
(ii)(11/7, -5/7 , 0) + lambda(1, -3, -7)
10
(i)8/21
(ii)1.183
 
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You have your p3 answers?

Mine:
1
(ii)12.2
2
(ii)4^(1/5)
3
(i)tan = (2root2 - 1)/(1 - root6)
(ii)128.4, 308.4
6
y = e^(x/2)
7
(a)1 - i and 20/8 + (4/8)i
8
(i)2- 4/(2+x) + 6/(3-2x)
(ii)2 + (7/3)x + (7/18)x^2
9
(i)56.9
(ii)(11/7, -5/7 , 0) + lambda(1, -3, -7)
10
(i)8/21
(ii)1.183
I'll do it in a day or two
Btw are u giving A2 only or composite?
 
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