Mathematics: Post your doubts here!

[Razo513]

can

For question 11 (a), use your calculator. If you are having a CASIO calculator of the fx brand use this method:
1. Use the In function
2. Enter the following into your calculator: In 0.125/In 2

For (b):
1. Change 512 to 2^9 so that all the numbers have the number 2 with a power.
2. Then do an equation:
4n+2n=9
3. Find the value of n
6n=9
n=9/6
n=1.5

Hope this was clear to you.

can i do this question in the same way?

 

[Razo513]

number 9 b) , c) , & d) whoever answers can u please explain too

 

[Razo513]

im not getting this question AT ALL!!

 

[ktc]

number 9 b) , c) , & d) whoever answers can u please explain too

Q.9] b) the probability that the first card chosen is S, out of the 4 cards = 2/4 [because out of 4 cards, 2 of them are letter S]

The probability that the second card chosen is S, out of the remaining 3 cards left = 1/3 [already one card has been picked out labeled S, now there is only one more remaining card labeled S, out of the 3 available cards]

Hence, 2/4 x 1/3 = 2/12


c) The probability that a card chosen from Set A is letter U, and not from Set B = 1/4 [only 1 card is labeled U, out of 4 cards in Set A] x 4/5 [out of the 5 cards in Set B, 4 cards are not labeled U]

1/4 x 4/5 = 1/5

The probability that a card chosen from Set B is letter U, and not from Set A = 1/5 [out of 5 cards in Set B, only 1 card is labeled U] x 3/4 [out of 4 cards in Set A, 3 of the cards are not labeled U]

1/5 x 3/4 = 3/20

So, 1/5 + 3/20 = 7/20

For part d) (Someone already asked the same question, before)

You should remember probability should be either I or U.

The probability that the 1st card is neither I nor U = 3/5 [out of 5 cards, 3 of them are neither I nor U]

The probability that the 2nd card is neither I nor U = 2/4 [out of the remaining 4 cards now, 2 of them are neither I nor U]

The probability that the 3rd card is neither I nor U = 1/3 [now out of the remaining 3 cards, only 1 card is neither I nor U]

The probability that the 4th card is either I or U = 1 [out of the remaining 2 cards, both of the cards are either I or U]

Hence, [3/5] x [2/4] x [1/3] x 1 = 6/60

im not getting this question AT ALL!!

Q.6]
2cm -> 4kg

6cm -> zkg

Therefore, [2*3] / [6*3] = 4/z

= 8/216 = 4/z

z = [216 x 4] / 8

z = 108kg

 

[Razo513]

ok

Q.9] b) the probability that the first card chosen is S, out of the 4 cards = 2/4 [because out of 4 cards, 2 of them are letter S]

The probability that the second card chosen is S, out of the remaining 3 cards left = 1/3 [already one card has been picked out labeled S, now there is only one more remaining card labeled S, out of the 3 available cards]

Hence, 2/4 x 1/3 = 2/12


c) The probability that a card chosen from Set A is letter U, and not from Set B = 1/4 [only 1 card is labeled U, out of 4 cards in Set A] x 4/5 [out of the 5 cards in Set B, 4 cards are not labeled U]

1/4 x 4/5 = 1/5

The probability that a card chosen from Set B is letter U, and not from Set A = 1/5 [out of 5 cards in Set B, only 1 card is labeled U] x 3/4 [out of 4 cards in Set A, 3 of the cards are not labeled U]

1/5 x 3/4 = 3/20

So, 1/5 + 3/20 = 7/20

For part d) (Someone already asked the same question, before)


Q.6]
2cm -> 4kg

6cm -> zkg

Therefore, [2*3] / [6*3] = 4/z

= 8/216 = 4/z

z = [216 x 4] / 8

z = 108kg

in Q 6 but why did u make 2* 3 /6*3 why didnt u just used a criss-cross method to calculate the mass ??

 

[ktc]

ok
in Q 6 but why did u make 2* 3 /6*3 why didnt u just used a criss-cross method to calculate the mass ??

You need to cube the heights to find the mass.

[Oh, and I just realized, I meant, 2^3 and 6^3]

 

[Razo513]

spo

You need to cube the heights to find the mass.

[Oh, and I just realized, I meant, 2^3 and 6^3]

so i consider this as a rule cubing the h when finding the mass?

 

[ktc]

spo
so i consider this as a rule cubing the h when finding the mass?

No. That is not a rule.

The volume of similar objects is directly proportional to the cube of their linear dimensions.

^ This one is.

Therefore, in the case of the eggs,

Ratio of volumes = [The ratio of the heights] ^3

In the question, it is given that both the eggs are made of chocolate [they are made of the same material] hence, they both have the same density.

As density = mass/volume. And both the eggs have the same density,

The volume of the eggs is directly proportional to mass.

Now, we can conclude the ratio of the mass = [The ratio of the heights] ^3

 

[lol]

Assalamoalaikum!!

Stuck somewhere in Maths?? Post your queries here! If you have any doubt in the pastpper questions, then kindly post the link to the paper!

P.S. I'm busy these days, so I can't promise to be there for help.

May Allah give us all success in this world as well as the HereAfter...Aameen!!

SEQUENCES-Points to remember:
Many people find it hard, but to be honest it's just more of logic..that's all!

Mathematics: Post your doubts here!

Salamoalaikom!

I am finding it extremely difficult to solve a question in maths PAPER 4. The link to the past paper is given below

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w04_qp_4.pdf

The part i can not solve is Question (10)(d)
i have no clue whatsoever on how to solve it, please help.
Also question (4)(f)(i) , when we stretch triangle ABC, why does 'A' also change its position to become 'A4' (3,2) according to the marking scheme? as it is being stretched, shouldn't one point atleast remain same/object not move? please explain

Thanks in advance! Jazaak Allah!

 

[shrawan]

can you please ?
send me a document explaining matrices and transformations
at
[email protected]
if you can your help will be really appreciated
but anyways
thank you

 

[Spidey21]

can you please ?
send me a document explaining matrices and transformations
at
[email protected]
if you can your help will be really appreciated
but anyways
thank you

you must be on facebook right?? search for the fb page math 4024
damn thats helpful even for add maths issues!!

 

[amir]

PLS HELP ME WITH Q NO 9 I CANNOT UNDER STAND IT I WILL BE GRATEFULL TI YA............

 

[Jay Jun]

PLS HELP ME WITH Q NO 9 I CANNOT UNDER STAND IT I WILL BE GRATEFULL TI YA............

try to expand (x+p)^2 then you'll know what to do.

 

[Razo513]

PLS HELP ME WITH Q NO 9 I CANNOT UNDER STAND IT I WILL BE GRATEFULL TI YA............

hope it's clear

 

[amir]

hope it's clear

thanks a lot i understood it thanks for helping

Are u also giving exams in may/june 2012.

 

[Razo513]

thanks a lot i understood it thanks for helping

Are u also giving exams in may/june 2012.

yes

 

[amir]

yes

ME TO
hope u get good grades work hard and i will now follow u ok.

 

[Razo513]

ME TO
hope u get good grades work hard and i will now follow u ok.

sure , thx u too gd luck

 

[amir]

q no 17 pls help me out..

 

[amir]

q no 17 pls help me out..

HELLO SOMEONE PLSS CAN U HELP ME WITH THIS QUESTION IF U DONT MIND HELPIN ME ......

PLS I AM STUCK........