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Mathematics: Post your doubts here!

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thx captain danger i just did it two hours ago :) and succeeded.....accha what does "and" "or" actually means in sets?
 
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can u suggest how to learn simple calculations of angle properties for cie exams
 
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is there any theoretical way to remember the colums which says " transform by the matrix " or i just have to memorize?
 

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is there any theoretical way to remember the colums which says " transform by the matrix " or i just have to memorize?
You just need to know how to make these matrices... Take 0,1 and 1,0 then rotate it or reflect it or do any of the transformation to get the resultant matrix...
 
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You just need to know how to make these matrices... Take 0,1 and 1,0 then rotate it or reflect it or do any of the transformation to get the resultant matrix...
but it also contains transformation of shear n stretch how do u do those?? :) kind of law isn't it?
 
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http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s08_qp_2.pdf
ques 1o

A cylindrical glass has a radius of 3 centimetres and a height of 7 centimetres.
A large cylindrical jar full of water is a similar shape to the glass.
The glass can be filled with water from the jar exactly 216 times.
Work out the radius and height of the jar.
_____________________________
i've been stuck on this question quite for a while. i know how to do it if we have to find only 1 item , but here there are two unknown values :/
* side-note: please help ASAP, the mock exam is tomorrow :/
 

ktc

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http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s08_qp_2.pdf
ques 1o

A cylindrical glass has a radius of 3 centimetres and a height of 7 centimetres.
A large cylindrical jar full of water is a similar shape to the glass.
The glass can be filled with water from the jar exactly 216 times.
Work out the radius and height of the jar.
_____________________________
i've been stuck on this question quite for a while. i know how to do it if we have to find only 1 item , but here there are two unknown values :/
* side-note: please help ASAP, the mock exam is tomorrow :/
The equation for the volume of a cylinder = πr^2h

Volume of the cylindrical glass:

= π (3^2) (7) = 197.92 cm3

It’s given the glass can be filled with water from the cylindrical jar 216 times.

Therefore, the volume of the jar = 197.92 x 216

= 42750.8 cm3

Both the cylinders are symmetrical, so to calculate the radius of the jar:

Let’s say, the radius of the jar = r

197.92/42750.8 = 3^3/r^3

r^3 =[27 x42750.8]/197.92]

r = 18 cm.

To calculate the height of the jar:

πr^2h = 42750.8 cm3

π (18^2) h = 42750.8 cm3

h = 42750.8 / [π (18^2)]

h = 42 cm.
 
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The equation for the volume of a cylinder = πr^2h

Volume of the cylindrical glass:

= π (3^2) (7) = 197.92 cm3

It’s given the glass can be filled with water from the cylindrical jar 216 times.

Therefore, the volume of the jar = 197.92 x 216

= 42750.8 cm3

Both the cylinders are symmetrical, so to calculate the radius of the jar:

Let’s say, the radius of the jar = r

197.92/42750.8 = 3^3/r^3 <<<<<<<<<<<<<<<i dont understand this step. can you please explain it? thank you

r^3 =[27 x42750.8]/197.92]

r = 18 cm.

To calculate the height of the jar:

πr^2h = 42750.8 cm3

π (18^2) h = 42750.8 cm3

h = 42750.8 / [π (18^2)]

h = 42 cm.

__________
other than that i get everything. thank you so much : )
 
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The equation for the volume of a cylinder = πr^2h

Volume of the cylindrical glass:

= π (3^2) (7) = 197.92 cm3

It’s given the glass can be filled with water from the cylindrical jar 216 times.

Therefore, the volume of the jar = 197.92 x 216

= 42750.8 cm3

Both the cylinders are symmetrical, so to calculate the radius of the jar:

Let’s say, the radius of the jar = r

197.92/42750.8 = 3^3/r^3

r^3 =[27 x42750.8]/197.92]

r = 18 cm.

To calculate the height of the jar:

πr^2h = 42750.8 cm3

π (18^2) h = 42750.8 cm3

h = 42750.8 / [π (18^2)]

h = 42 cm.
______________

lol omg i think i got just it now,, did you use volume = scale factor cube?
 

ktc

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__________
other than that i get everything. thank you so much : )
______________

lol omg i think i got just it now,, did you use volume = scale factor cube?
I used similarity ;)

We wanna find the radius of the jar.

Since the jar and the glass are both similar to one another;

The ratio of their volumes is equal to the ratio of their radii.

The ratio of the volumes = 197.92/42750.8

The ratio of the radii = 3^3/r^3

But since your equating the radius to the volume, you should cube the radius, to do so.

Therefore it will be [197.92/42750.8] = 3^3/r^3

Now comes Algebra.

r^3 =[27 x42750.8]/197.92]

r = 18 cm.
 
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I used similarity ;)

We wanna find the radius of the jar.

Since the jar and the glass are both similar to one another;

The ratio of their volumes is equal to the ratio of their radii.

The ratio of the volumes = 197.92/42750.8

The ratio of the radii = 3^3/r^3

But since your equating the radius to the volume, you should cube the radius, to do so.

Therefore it will be [197.92/42750.8] = 3^3/r^3

Now comes Algebra.

r^3 =[27 x42750.8]/197.92]

r = 18 cm.

ohhh :O alright. thanks :D
 
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but it also contains transformation of shear n stretch how do u do those?? :) kind of law isn't it?

Same for shear and stretch... Invariant lines remain the same... If its (1,0) and x axis is invariant it stays the same... Same goes for y axis...
 
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The equation for the volume of a cylinder = πr^2h

Volume of the cylindrical glass:

= π (4^2) (6) = 301.59 cm3

It’s given the glass can be filled with water from the cylindrical jar 216 times.

Therefore, the volume of the jar = 301.59 x 216

= 65144.1 cm3

Both the cylinders are symmetrical, so to calculate the radius of the jar:

Let’s say, the radius of the jar = r

301.59/65144.1 = 4^3/r^3

r^3 =[64 x 65144.1]/301.59]

r = 24 cm.

To calculate the height of the jar:

πr^2h = 65144.1 cm3

π (24^2) h = 65144.1 cm3

h = 65144.1/ [π (24^2)]

h = 36 cm.

Draw a Venn diagram. It makes the question sound a whole lot easier that way.

Let’s say, n(TGM) = x

The equation used when it comes to 3 sets being involved is:

n(T)+n(G)+n(M) - {(nTG)+n(GM)+n(TM} +n(TGM) = 150 - n(T'G'M')

= 40 + 35 + 60 – [7 + 10 + 4 + x) = 150 – 34

= 114 + x = 116

x = 116 – 114

x = 2

Hence, 2 houses receive all three.
can u make a diagram? a Venn diagram..? because I don't know how to make one..
 
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can someone please explain how question 9(d) is done please? i've tried it ever so many times but my result is always wrong :/

(d) A card is chosen at random, without replacement, from Set B until the letter shown is either
I or U.
Find the probability that this does not happen until the 4th card is chosen.
_
Thank you :)
 

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please help me solve this question. and a little bit on how these questions are normally solved.
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the area of a rectangle is 52cm^2 , the breath is 1.5cm less than its length. find the length and the breadth.
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i'd really appreciate it if someone would answer this. thank you.
 
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