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Chemistry: Post your doubts here!

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467
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number3 outer energy level should hhave one electron which is the case in B
number-12 i think thats the correct answer.
pi bond is formed by sideways overlap of p orbital in partD its i think diagonal sort of overlap whereas in partB its side ways overlap i suppose you would be confused by seing in part-B that its s orbital but no its p orbital bcause see clearly nucleus is in the middle of two circles so its lobe shaped which is p orbital
hope it helps:)
 
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in 16 read the question again. it says the cell is kept cold. with cold Naoh NaClO is formed not NaClO3. you"ve to learn these rxns.
in 36, nitrogen dioxide is very much polar. positive nitrogen atom and 2 negative oxygen hence overall is it polar!

yes actually i know those reactions but i never really considered them to be involved here!
And i was just coming around to understanding how NO2 is polar because of the difference in electronegativities.
Well thanks a lot!
 
Messages
467
Reaction score
101
Points
53
in 16 read the question again. it says the cell is kept cold. with cold Naoh NaClO is formed not NaClO3. you"ve to learn these rxns.
in 36, nitrogen dioxide is very much polar. positive nitrogen atom and 2 negative oxygen hence overall is it polar!
please can you explain how no for basic hydride.
thanks
 
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Use of the Data Booklet is relevant to this question.
What could be the proton number of an element that has three unpaired electrons in each of its
atoms?
A 5 B 13 C 15 D 21
why C.... why not B
 
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5 Given the following enthalpy changes,
I2(g) + 3Cl2(g) → 2ICl3(s) ∆H = –214kJmol
I2(s) → I2(g) ∆H = +38kJmol

What is the standard enthalpy change of formation of iodine trichloride, ICl3(s)?
A +176kJmol
B –88kJmol
C –176kJmol
D –214kJmol
 
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2.920 g of a Group II metal, X, reacts with an excess of chlorine to form 5.287 g of a compound
with formula XCl2.
What is metal X?
A barium
B calcium
C magnesium
D strontium
 
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2.920 g of a Group II metal, X, reacts with an excess of chlorine to form 5.287 g of a compound
with formula XCl2.
What is metal X?
A barium
B calcium
C magnesium
D strontium
the formula XCL2 shows i mole of X's mass will cover 2 of Cl ....so see the RMM of any of the options whose mass is close to 2*Cl
Cl-35.5X2=71
Ba-137...so nt possible
Ca-40....agn nt possible
Mg-24....does not = to 71
Sr-88....closest to 71...so D
u can also do the mole ratio: Mass/RMM
 
Messages
16
Reaction score
3
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3
Given the following enthalpy changes,
I2(g) + 3Cl2(g) → 2ICl3(s) ∆H = –214kJmol
I2(s) → I2(g) ∆H = +38kJmol

What is the standard enthalpy change of formation of iodine trichloride, ICl3(s)?
A +176kJmol
B –88kJmol
C –176kJmol
D –214kJmol
 
Messages
347
Reaction score
17
Points
28
Given the following enthalpy changes,
I2(g) + 3Cl2(g) → 2ICl3(s) ∆H = –214kJmol
I2(s) → I2(g) ∆H = +38kJmol

What is the standard enthalpy change of formation of iodine trichloride, ICl3(s)?
A +176kJmol
B –88kJmol
C –176kJmol
D –214kJmol
whats the answer?
 
Messages
16
Reaction score
3
Points
3
Given the following enthalpy changes,
I2(g) + 3Cl2(g) → 2ICl3(s) ∆H = –214kJmol
I2(s) → I2(g) ∆H = +38kJmol

What is the standard enthalpy change of formation of iodine trichloride, ICl3(s)?
A +176kJmol
B –88kJmol
C –176kJmol
D –214kJmol​
whats the answer?...........................

its B
 
Messages
347
Reaction score
17
Points
28
Given the following enthalpy changes,​
I2(g) + 3Cl2(g) → 2ICl3(s) ∆H = –214kJmol​
I2(s) → I2(g) ∆H = +38kJmol​
What is the standard enthalpy change of formation of iodine trichloride, ICl3(s)?​
A +176kJmol​
B –88kJmol​
C –176kJmol​
D –214kJmol​
whats the answer?...........................

its B
its going to be 2x - 38 = -214. solve for x.
 
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