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i need mark scheme for june 99 .. any help ?
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june 1999...i dont think so any1 has it...i need mark scheme for june 99 .. any help ?
i was doing that paper and found it confusing .. :/june 1999...i dont think so any1 has it...
it depends on the graph... usually if you're taking x as the midpoint of the oscillation when t=0, then it's a sine graph. If you're taking x as the maximum amplitude position when t=0, its a cosine graph.can any1 plz tell me wen to use cos and wen to use sine in any kind of oscillation...
can you upload the paper? Let's do it together.. I'm tired of reading the textbook..i was doing that paper and found it confusing .. :/
so write what the Q is ....is we can answer them?i was doing that paper and found it confusing .. :/
ya dat would be better...can you upload the paper? Let's do it together.. I'm tired of reading the textbook..
plz ppl answer my this Q....can any1 plz tell me wat is meant by Analoge signal and Digital signal?
Digital Signal is the one in which there is a series of pulses btw descrete levels and in Analogue, the waveform of signal is in a similar manner as to the waveform of sound wave producing itcan any1 plz tell me wat is meant by Analoge signal and Digital signal?
what does this means that...digital has no intermediate values...Digital Signal is the one in which there is a series of pulses btw descrete levels and in Analogue, the waveform of signal is in a similar manner as to the waveform of sound wave producing it
only two values 1 and 0 . no intermediate value . no curve in the graph . a horizontal line at 1 or a horizontal line at 0what does this means that...digital has no intermediate values...
ans..i..1/2QV...1/2*1.6*10^-19*(-200-(-9000))(A)Electrons in a cathode-ray tube leave the cathode with negligible speed at a potential of -9000V and are accelerated to an anode at a potential of -200V. For an electron in this tube calculate
(i) the gain in electrical energy
(ii)the loss in potential energy
(iii)the gain in kinetic energy
(iv)the speed on reaching the anode
(B) Explain why (A)(i) is a gain but (A)(ii) is a loss.
and wt does this means that...for analoge..signal has same varitaion (wit time) as the data...only two values 1 and 0 . no intermediate value . no curve in the graph . a horizontal line at 1 or a horizontal line at 0
yeah i did the same . and the gain in K.E would be equal to loss in P.E and we can find the speed by equating the K.E to 1/2mv^2 . Am i right?ans..i..1/2QV...1/2*1.6*10^-19*(-200-(-9000))
so ans might be 7.04*10^-16...i guess...for the first 1
ya i guess...lolyeah i did the same . and the gain in K.E would be equal to loss in P.E and we can find the speed by equating the K.E to 1/2mv^2 . Am i right?
now wat would be the reason for B?yeah i did the same . and the gain in K.E would be equal to loss in P.E and we can find the speed by equating the K.E to 1/2mv^2 . Am i right?
it means that the signal has the same sketching or shape of graph as the dataand wt does this means that...for analoge..signal has same varitaion (wit time) as the data...
where'd you get the -200 from?ans..i..1/2QV...1/2*1.6*10^-19*(-200-(-9000))
so ans might be 7.04*10^-16...i guess...for the first 1
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