Physics, Chemistry and Biology: Post your doubts here!

thats_me

thats_me

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ZainH said:
All right.. one more time.
Did you see the question? In part (a) they ask you to record the reading on the ameter, which is 0.3. This reading is "Io", and in the next part of the question it says 0.5Io, which is 0.5 x Io. We already know what Io is so just multiply.
0.5x0.3= 0.15

Now take a look at the table, under the current column, the last reading is 0.15A. But there is no resistance..
Part b)ii) of the question asks to write the combined resistance of resistors 3.3 and 6.8 in series. Just add,
3.3+6.8= 10.1

NOW, the theory says the current will be 0.15 A ONLY when the TOTAL resistance in the circuit is 2x that of resistor X.
We already know that the COMBINED resistance of the other 2 resistors was 10.1, and the total resistance should be 2 times resistor X's.
So we can now make an equation if we take the resistance of resistor X as "R" (Just a variable)

R + 10.1 = 2R
10.1 = R

Resistor X's resistance = 10.1 Ohms.

Hope you got it this time x)
Click to expand...
can u help me with O/N 8 1d
 
K

knightwalker

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ZainH said:
All right.. one more time.
Did you see the question? In part (a) they ask you to record the reading on the ameter, which is 0.3. This reading is "Io", and in the next part of the question it says 0.5Io, which is 0.5 x Io. We already know what Io is so just multiply.
0.5x0.3= 0.15

Now take a look at the table, under the current column, the last reading is 0.15A. But there is no resistance..
Part b)ii) of the question asks to write the combined resistance of resistors 3.3 and 6.8 in series. Just add,
3.3+6.8= 10.1

NOW, the theory says the current will be 0.15 A ONLY when the TOTAL resistance in the circuit is 2x that of resistor X.
We already know that the COMBINED resistance of the other 2 resistors was 10.1, and the total resistance should be 2 times resistor X's.
So we can now make an equation if we take the resistance of resistor X as "R" (Just a variable)

R + 10.1 = 2R
10.1 = R

Resistor X's resistance = 10.1 Ohms.

Hope you got it this time x)
Click to expand...

THANK YOOOUUU I GET IT NOWW !!!
 
J

JOEJOE

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ITS a kind of pointer that is used to measure length! it doesnt matter if its a device or no just draw a pointer and the bottom and draw a ruler beside it................... its 1 mark anyway so
 
Z.A.M

Z.A.M

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JOEJOE said:
ITS a kind of pointer that is used to measure length! it doesnt matter if its a device or no just draw a pointer and the bottom and draw a ruler beside it................... its 1 mark anyway so
Click to expand...
Thanx
 
ZainH

ZainH

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thats_me said:
lol :p thx
Click to expand...

All right so basically there asking, if you use a longer piece of metal with the same mass , would the extension be the same?
Obviously not, it would be greater.
The next part asks if the density would be the same, and since according to the formula they have provided if E2 increases, so does your density x)

Hope you got it!
 
ZainH

ZainH

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AAnsarii said:
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_61.pdf
4(c) ...?
Click to expand...

Er for this question, you can't really explain it over XPC..
Thing is you have to first solve the whole question , which requires drawing lines and measuring angles..
But basically for that part they're asking , if the mirror is moved at an angle of theta (which is 10 degrees, it's given in the question.. they ask you to reflect it at an angle of 10 degrees) will the reflected ray move twice as much, so 20 degrees. It all depends on what you get for part (iv).
 
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