Physics, Chemistry and Biology: Post your doubts here!

[Z.A.M]

Thanx ZainH just got that question it's easy

 

[ZainH]

Thanx ZainH just got that question it's easy

Anytime, I didn't get it at first either but then Yousif Mukkhtar explained it to me x)

 

[thats_me]

All right.. one more time.
Did you see the question? In part (a) they ask you to record the reading on the ameter, which is 0.3. This reading is "Io", and in the next part of the question it says 0.5Io, which is 0.5 x Io. We already know what Io is so just multiply.
0.5x0.3= 0.15

Now take a look at the table, under the current column, the last reading is 0.15A. But there is no resistance..
Part b)ii) of the question asks to write the combined resistance of resistors 3.3 and 6.8 in series. Just add,
3.3+6.8= 10.1

NOW, the theory says the current will be 0.15 A ONLY when the TOTAL resistance in the circuit is 2x that of resistor X.
We already know that the COMBINED resistance of the other 2 resistors was 10.1, and the total resistance should be 2 times resistor X's.
So we can now make an equation if we take the resistance of resistor X as "R" (Just a variable)

R + 10.1 = 2R
10.1 = R

Resistor X's resistance = 10.1 Ohms.

Hope you got it this time x)

can u help me with O/N 8 1d

 

[knightwalker]

All right.. one more time.
Did you see the question? In part (a) they ask you to record the reading on the ameter, which is 0.3. This reading is "Io", and in the next part of the question it says 0.5Io, which is 0.5 x Io. We already know what Io is so just multiply.
0.5x0.3= 0.15

Now take a look at the table, under the current column, the last reading is 0.15A. But there is no resistance..
Part b)ii) of the question asks to write the combined resistance of resistors 3.3 and 6.8 in series. Just add,
3.3+6.8= 10.1

NOW, the theory says the current will be 0.15 A ONLY when the TOTAL resistance in the circuit is 2x that of resistor X.
We already know that the COMBINED resistance of the other 2 resistors was 10.1, and the total resistance should be 2 times resistor X's.
So we can now make an equation if we take the resistance of resistor X as "R" (Just a variable)

R + 10.1 = 2R
10.1 = R

Resistor X's resistance = 10.1 Ohms.

Hope you got it this time x)

THANK YOOOUUU I GET IT NOWW !!!

 

[za Shadow]

Fiduciual aid means that u add a pointer to the spring at the bottom then place a ruler and measure the length!

so its not a device???!!!

 

[Z.A.M]

ya i saw it in a physics P6 question and i don't know what is it

Yes it is I saw it too
Have no idea wat it means anyone?

 

[AAnsarii]

amm i still don't understand it plzz in simple words​

look at d other link i just added..

 

[Z.A.M]

so its not a device???!!!

Ok thanx

 

[JOEJOE]

ITS a kind of pointer that is used to measure length! it doesnt matter if its a device or no just draw a pointer and the bottom and draw a ruler beside it................... its 1 mark anyway so

 

[ZainH]

THANK YOOOUUU I GET IT NOWW !!!

Glad to help others, just pray for me ( Especially chemistry LOL xD )

can u help me with O/N 8 1d

Sure just let me read the question and see if I know the answer x)

 

[Z.A.M]

ITS a kind of pointer that is used to measure length! it doesnt matter if its a device or no just draw a pointer and the bottom and draw a ruler beside it................... its 1 mark anyway so

Thanx

 

[AAnsarii]

Great! i just hope it doesnt ta ke up max space in r ppr...

 

[za Shadow]

look at d other link i just added..

thnx

 

[za Shadow]

ITS a kind of pointer that is used to measure length! it doesnt matter if its a device or no just draw a pointer and the bottom and draw a ruler beside it................... its 1 mark anyway so

THANK U SOOO MUCH

 

[thats_me]

Glad to help others, just pray for me ( Especially chemistry LOL xD )



Sure just let me read the question and see if I know the answer x)

lol thx

 

[AAnsarii]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_61.pdf
4(c) ...?

 

[Lost_Life]

guys how do we find the thickness of a cylinder

 

[ZainH]

lol thx

All right so basically there asking, if you use a longer piece of metal with the same mass , would the extension be the same?
Obviously not, it would be greater.
The next part asks if the density would be the same, and since according to the formula they have provided if E2 increases, so does your density x)

Hope you got it!

 

[AAnsarii]

guys how do we find the thickness of a cylinder

use a vernier caliper
http://www.physics.smu.edu/~scalise/apparatus/caliper/

 

[ZainH]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_61.pdf
4(c) ...?

Er for this question, you can't really explain it over XPC..
Thing is you have to first solve the whole question , which requires drawing lines and measuring angles..
But basically for that part they're asking , if the mirror is moved at an angle of theta (which is 10 degrees, it's given in the question.. they ask you to reflect it at an angle of 10 degrees) will the reflected ray move twice as much, so 20 degrees. It all depends on what you get for part (iv).