AS Physics P1 MCQs Preparation Thread.

[leosco1995]

I will tilt them next time thanks, Also thanks for the answer to the graph question that really helped me!!! However, the first question about the compression and tension, your answer is wrong, the answer is actually Tension at X AND Y, and compression at Z ... which doesnt follow what you said....

Oops. I meant tension at X and Y and compression at Z. My reasoning is still correct, I just read the diagram wrong.

Would be painful for something like that to happen in the exam. :\

 

[leosco1995]

MJ 2007 ques 23, help plz

I just explained this one.

http://www.xtremepapers.com/community/posts/319447

 

[geek101]

MJ 2007 ques 23, help plz

this related to simple harmonic motion...which says...

• The speed is maximum when the object passes through the equilibrium position (x = 0)
• The acceleration is opposite in direction, and proportional to, the displacement

so just apply this to this to the question youll get your answer...

 

[shan5674]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf 25, help pls?

 

[leosco1995]

why do you multiply the change in momentum by -1?

My original expression for the change in momentum was p2 - p1. But none of the options given in the question had that, so I had to multiply the entire expression by -1 to give -p2 + p1, i.e. p1 - p2 which still contains the same magnitude as my original expression. Normally you wouldn't do that for a momentum question since it's a vector quantity but here you can because they asked for the magnitude only, multiplying by -1 just rearranged my expression to get the same expression in option B.

 

[geek101]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf 25, help pls?

first calculate the wavelength...
lambda = speed / frequency
= 340 / 500
= 0.68

now use the formula for phase difference = 360 (x/lambda) where x is the distance between the two waves
so phase diff = 360 ( 0.17 / 0.68) = 90 degrees
the answers are in radians so just convert 90 degrees is pii/2 and the answer is B

 

[leosco1995]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf 25, help pls?

A formula for phase difference:

(distance between 2 points / one wavelength) * 2π

One wavelength in this case is 340 / 500 = 0.68

Applying the formula,

(0.17 / 0.68) * 2π gives us π/2 radian.

 

[leosco1995]

first calculate the wavelength...
lambda = speed / frequency
= 340 / 500
= 0.68

now use the formula for phase difference = 360 (x/lambda) where x is the distance between the two waves
so phase diff = 360 ( 0.17 / 0.68) = 90 degrees
the answers are in radians so just convert 90 degrees is pii/2 and the answer is B

Damn you are quick.

 

[SalamH]

ppl pleez explain d followin
12/o/n/09-Q5,Q16,Q25
01/M/J/03-Q6,Q10,Q20,Q23,Q40

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_12.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf
I 'm askin for d sec tym pls explain

 

[Silent Hunter]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s09_qp_1.pdf

Q10,15,18 THANK YOU

 

[USMAN Sheikh]

anyone pls exp these ques 23 25 35 nd40 for 35 why voltmeter reading is zero ammeterreadgis clear need help pls gys

 

[A.ELWY 7]

anyone pls exp these ques 23 25 35 nd40 for 35 why voltmeter reading is zero ammeterreadgis clear need help pls gys

Q23: FIRST U GET THE FREQUENCY USING V=f ( lambda)..according to the graph one wavelength is 50m so 8/50=0.16Hz...then u get the speed of the particle which is 2 x (pie) x a x f....amplitude = 2...substitue so 2 x ( pie) x 2 x 0.16= 2 ms^-1...then 1/2 mv^2= 0.5 x 0.002 x 2 = 4 x 10^-3 so 4mJ so B
Q25: B because we have three beams + the normal beam going straight away so 4
Q35:SRY CAN'T HELP ON THIS ONE
Q40: it is A because an alpha particle consists of 2 protons and 2 neutrons and so the greates mass of the four..and MOMENTUM is mv so A is the answer

 

[kinglynx]

https://fbcdn-sphotos-a.akamaihd.ne...x720/282891_10150999944406535_846620522_n.jpg

Simple question , i think its because the young modulus is higher but can anyone please confirm this for me??

 

[leosco1995]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf

Q10,15,18 THANK YOU

10) First find the velocity with which the masses explode into (using the conservation of momentum formula):

Let x be the speed of body 'm', and y be the speed of body '2m'.

0 = mx - 2my
mx = 2my
x = 2y

That means body 'm' has a speed of x, and body '2m' has a speed of x/2.

Using the K.E formula, the ratio is:

(0.5 * 2 * x^2) / (0.5 * 2 * (x/2)^2)

Which results in 2:1.

Q15) Let the original P.E in X be mgh.

When both vessels have equal depths of water, x loses half its mass and half its depth.

New P.E = (m/2) * g * (h/2) = mgh/4.

Q18) If the RHS increases by a distance 'h', the LHS will decrease by a distance 'h'.

The pressure is ρg * 2h = 2hρg.

 

[AppleGreen]

this related to simple harmonic motion...which says...

• The speed is maximum when the object passes through the equilibrium position (x = 0)
• The acceleration is opposite in direction, and proportional to, the displacement

so just apply this to this to the question youll get your answer...

I just explained this one.

http://www.xtremepapers.com/community/posts/319447

thx!

 

[A.ELWY 7]

https://fbcdn-sphotos-a.akamaihd.ne...x720/282891_10150999944406535_846620522_n.jpg

Simple question , i think its because the young modulus is higher but can anyone please confirm this for me??

i think it is because steel is a mixture of iron and carbon so it may have the resistance of two substances to be deformed while aluminium is a single metal substance which is more able to be deformed

 

[kinglynx]

10) First find the velocity with which the masses explode into (using the conservation of momentum formula):

Let x be the speed of body 'm', and y be the speed of body '2m'.

0 = mx - 2my
mx = 2my
x = 2y

That means body 'm' has a speed of x, and body '2m' has a speed of x/2.

Using the K.E formula, the ratio is:

(0.5 * 2 * x^2) / (0.5 * 2 * (x/2)^2)

Which results in 2:1.

Q15) Let the original P.E in X be mgh.

When both vessels have equal depths of water, x loses half its mass and half its depth.

New P.E = (m/2) * g * (h/2) = mgh/4.

Q18) If the RHS increases by a distance 'h', the LHS will decrease by a distance 'h'.

The pressure is ρg * 2h = 2hρg.

why dont you multiply by two for question 15? ... i mean you have two containers each with mgh/4 , thus that wud leave u with mgh/2 ???

also Q18) why would you include the decrease of a distance on the LHS, like can you explain it?

 

[USMAN Sheikh]

Q23: FIRST U GET THE FREQUENCY USING V=f ( lambda)..according to the graph one wavelength is 50m so 8/50=0.16Hz...then u get the speed of the particle which is 2 x (pie) x a x f....amplitude = 2...substitue so 2 x ( pie) x 2 x 0.16= 2 ms^-1...then 1/2 mv^2= 0.5 x 0.002 x 2 = 4 x 10^-3 so 4mJ so B
Q25: B because we have three beams + the normal beam going straight away so 4
Q35:SRY CAN'T HELP ON THIS ONE
Q40: it is A because an alpha particle consists of 2 protons and 2 neutrons and so the greates mass of the four..and MOMENTUM is mv so A is the answer

thanks alot dude can anyone help me on 35 ??????

 

[USMAN Sheikh]

can anyone pls help me out on these question plssss 6 24 30 34 pls

 

[hmlahori]

I know this is a lot of questions but please do help fellows. Thanks........

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s07_qp_1.pdf
http://www.xtremepapers.com/papers/...A and AS Level/Physics (9702)/9702_s07_er.pdf
Q8 Q10 Why isnt answer D? average force= change in P/change in t = (-p2-p1)/(t2-t1) =(simplifying) (p1+p2)/(t2-t1) rite??
Q13, 20 Q 23 Why not A? Q40 How do we find its answer. Examiner report mentions q/m ratio has to be lowest. what is q/m ratio??

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_qp_1.pdf
http://www.xtremepapers.com/papers/...A and AS Level/Physics (9702)/9702_s08_er.pdf
Q6 Why wont there be a change in speed if the object is accelerating?
Q13, 14 am always get these type of questions wrong....any particular method to solve them?
Q22 Why not B? And what is the difference btw limit of proportionality and elastic limit?
Q 24??? How do we solve it? i got 8E and thats not even one of the options. if diameter is halved then doesnt the area decrease by a factor of four and length is doubled so by simplifying we get 8E. But answer is E.......