maths help needed..!

[immi1234]

Can someone explain upper quartile, lower quartile, upper bound, lower bound to me..?

 

[CaptainDanger]

http://www.mathsteacher.com.au/year9/ch17_statistics/06_quartiles/quartiles.htm

 

[Muhammad TAimoor]

Can someone explain upper quartile, lower quartile, upper bound, lower bound to me..?

Remember it like this. Upper Quartile is 3/4th part of Frequency and Lower Quartile is 1/3rd e.g if the total frequency is 100, its upper quart will be 75 and lower would be 25. Just find the Value on the x-axis from the graph, that'll be ur answer.

 

[AlphaBeta]

http://www.mathsteacher.com.au/year9/ch17_statistics/06_quartiles/quartiles.htm

help in congruency

 

[sabasi]

Remember it like this. Upper Quartile is 3/4th part of Frequency and Lower Quartile is 1/3rd e.g if the total frequency is 100, its upper quart will be 75 and lower would be 25. Just find the Value on the x-axis from the graph, that'll be ur answer.

lower quartile is 1/4 of total frequency

 

[sabasi]

http://www.mathsteacher.com.au/year9/ch17_statistics/06_quartiles/quartiles.htm

Upper bound and Lower bound ???????? Can u tell please ?

 

[CaptainDanger]

Upper bound and Lower bound ???????? Can u tell please ?

Upper bound, lower bound

 

[Minnie]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w11_qp_22.pdf
Q3 please? i dont get how to do it.

 

[CaptainDanger]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_22.pdf
Q3 please? i dont get how to do it.

One of the parts is solved here : Maths, Addmaths and Statistics: Post your doubts here!

Post your doubt in the same <Maths, Addmaths and Statistics: Post your doubts here!> thread again for the rest of the parts...

 

[Zain Salman Dar]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_22.pdf
Q3 please? i dont get how to do it.

ai) 1 line of symmetry
aii) 360/5= 72
( 72/360*pi*R^2)/2 = pi*r^2
R^2/10 = r^2
From the above equation radius of smaller circle is equal to 1/10 of the radius of larger circle = R^2: r^2 = 10:1
bi) concept of cyclic quadrilateral. Centre angle = 72, angle opposite of it= 180-72=108. Reflex angle= 360-108= 253 [Hence proved]
bii) Circumference of larger sector = 252/360*2*pi*r*5= 7*pi*r=k=7