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(x-2)^2 + y^2 =r^2 is this a formula used to find the solution for these type of questions?
And it's still not v clear so can u please solve it?
Thnx
If a circle of radius r is centered at (a,b), then its cartesian equation is given by (x-a)^2+ (y-b)^2 =r^2 . In your question, a=2 while b=0.
Hope this helps. Peace.