Physics P1 - Last 3 Days Discussion

[W-inx]

Post all your problems here and let's solve them

 

[Sheikh Nahiyan]

Oct-Nov'11 (11) Question - 4, 28,29,30, 33

May-June'11 (11) Question - 13,14,24,25,27,30

 

[khan0000]

m/j 11 Q3 Q 5 Q6 help ps?

 

[khan0000]

Q 19

 

[khan0000]

Q 17

 

[monkeys12]

how to do this?

 

[Daniyal23]

34. Two copper wires X and Y have the same volume. Wire Y is four times as long as wire X.

What is the ratio
resistance of wire X
____________
resistance of wire Y
?
A 4, B 8, C 16, D 64

Ans is C
How did they find the answer?

 

[Prawesh Dahal]

34. Two copper wires X and Y have the same volume. Wire Y is four times as long as wire X.

What is the ratio
resistance of wire X
____________
resistance of wire Y
?
A 4, B 8, C 16, D 64

Ans is C
How did they find the answer?

Well, im supposing & as resisitivity
so R= & L/A but theres another formula for R in volume case...if u multiply the numerator and denominator by L. u get

R = & L x L / A x L ----> ( A x L ) is volume.
So, R is also,
= & L^2/ V ! Use this and u will get the ans. You can already predict, 4L gets squared and u get 16 as the ratio.

 

[Goku]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w03_qp_1.pdf

Someone please help me with 2,4,5,7,13,24,28,31,37

Please please please?!!

 

[ICTloverz]

How to calculate the vertical component when you're provided with horizontal component and an angle.

 

[Daniyal23]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s09_qp_1.pdf
Q10 hurry please exam in few hours..

 

[bamteck]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf
Q10 hurry please exam in few hours..

C...the momentum of body m must equal the momentum of body 2m..this means that if body m has half the mass so it must have double the velocity so ratio of kinetic energy of m /2m = ( 0.5 m x 2v^2)/ (0.5 x 2m x v^2) so it will be 2/1

 

[InnocentAngel]

plz help xms in 2 hrs

 

[Mattman]

Potential energy is gained, so

PE=Work lost(charge is moving away from electric field)
PE=Forcexdistance moved in that direction