HALPPPP! IM DYING!!!!!!!!!1

[Rutzaba]

ahem... now can someone do the partial fractions in this and make this in a form i can integrate?

x^2 -2x+3
(x-1)(x^2 +2x+2)

please do the partial fractions clearly...

 

[Steel Arm]

ok sssoooo
x^2 -2x+3
(x-1)(x^2 +2x+2) is equal to A/(x-1) + (Bx + c)/(x^2 + 2X + 2)

so if we take an LCM of (x-1)(x^2 +2x+2)
the numerators are
A(x^2 +2x+2) + (Bx +C)(x-1)
these should be equal to the original numerators x^2 -2x+3
so its supposed to be

x^2 -2x+3 = A(x^2 +2x+2) + (Bx +C)(x-1)
now we take x=1 to eliminate Bx+C
u get.... 1-2+3=5A
A=2/5

now u consider coefficients of x^2
x^2 = Ax^2 + Bx^2
1=A+B
A=2/5 therefore, B=3/5

now finally, to get value of C.... you take coeff of x
-2x=2Ax-Bx+Cx
-2=2A-B+C
A=2/5 and B=3/5..... u replace in equation
C=-11/5

FINALLY its
2/5/x-1 + ((3/5)x - 11/5)/(x^2 +2x+2)

its kinda difficult to show here...... if u dont understand sthing still tell me.....

 

[marshall mathers]

You can also expand and compare coefficients to cross check.

 

[Steel Arm]

You can also expand and compare coefficients to cross check.

ahaan.... thts wat i did in fact.....

 

[Nibz]

I didn't know a math problem could be so deadly.

 

[Rutzaba]

ok sssoooo
x^2 -2x+3
(x-1)(x^2 +2x+2) is equal to A/(x-1) + (Bx + c)/(x^2 + 2X + 2)

so if we take an LCM of (x-1)(x^2 +2x+2)
the numerators are
A(x^2 +2x+2) + (Bx +C)(x-1)
these should be equal to the original numerators x^2 -2x+3
so its supposed to be

x^2 -2x+3 =A(x^2 +2x+2) + (Bx +C)(x-1)
now we take x=1 to eliminate Bx+C
u get.... 1-2+3=5A
A=2/5

now u consider coefficients of x^2
x^2 = Ax^2 + Bx^2
1=A+B
A=2/5 therefore, B=3/5

now finally, to get value of C.... you take coeff of x
-2x=2Ax-Bx+Cx
-2=2A-B+C
A=2/5 and B=3/5..... u replace in equation
C=-11/5

FINALLY its
2/5/x-1 + ((3/5)x - 11/5)/(x^2 +2x+2)

its kinda difficult to show here...... if u dont understand sthing still tell me.....

thankoooooo ab ye akhri term ko integrate ... ((3/5)x - 11/5)/(x^2 +2x+2) plz

 

[Rutzaba]

bure bhai... thnks anyways badrobot14

 

[Steel Arm]

thankoooooo ab ye akhri term ko integrate ... ((3/5)x - 11/5)/(x^2 +2x+2) plz

hhmmm.... u've gotta tell me up to which powers of x..... ??????

 

[Rutzaba]

dude.. i dun want u to expand... integrate this.... or may be now we will substitute

 

[Steel Arm]

dude.. i dun want u to expand... integrate this.... or may be now we will substitute

ooopss soorrryyy i misread tht

 

[Nibz]

dude.. i dun want u to expand... integrate this.... or may be now we will substitute

Maybe, you should ask more politely.

 

[Rutzaba]

ooopss soorrryyy i misread tht

dun wrry... can u do it? the answer involves tan...

 

[Rutzaba]

Maybe, you should ask more politely.

duz it matter steel arm? any ways moddy says soo... pleeeesh integrate thisss ?

 

[Steel Arm]

dun wrry... can u do it? the answer involves tan...

well to be frnk... this time i'm stuck.... ....... sorry....

 

[Steel Arm]

duz it matter steel arm? any ways moddy says soo... pleeeesh integrate thisss ?

i didnt mind...
and i dont know how to do it anyway....

 

[Rutzaba]

thnkoooo soooo much bro u be love <3 i think il do it from hre...

 

[Steel Arm]

thnkoooo soooo much bro u be love <3 i think il do it from hre...

Gud Luck!!!

 

[Rutzaba]

i think i think i think....
x^2 +2x +2
can be said as (x+1)^2 +1 let x+1 be u
u^2 +1 can be done with the formula... 1/a tan inverse (x/a)

 

[Steel Arm]

i think i think i think....
x^2 +2x +2
can be said as (x+1)^2 +1 let x+1 be u
u^2 +1 can be done with the formula... 1/a tan inverse (x/a)

but x^2 +2x +2 is not equal to (x+1)^2......
try to expand (x+1)^2.... u wont get x^2 + 2x + 2

 

[badrobot14]

bure bhai... thnks anyways badrobot14

sorry.. was busy.. X_X