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HALPPPP! IM DYING!!!!!!!!!1

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ahem... now can someone do the partial fractions in this and make this in a form i can integrate?

x^2 -2x+3
(x-1)(x^2 +2x+2)

please do the partial fractions clearly...
 
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ok sssoooo
x^2 -2x+3
(x-1)(x^2 +2x+2) is equal to A/(x-1) + (Bx + c)/(x^2 + 2X + 2)

so if we take an LCM of (x-1)(x^2 +2x+2)
the numerators are
A(x^2 +2x+2) + (Bx +C)(x-1)
these should be equal to the original numerators x^2 -2x+3
so its supposed to be

x^2 -2x+3 = A(x^2 +2x+2) + (Bx +C)(x-1)
now we take x=1 to eliminate Bx+C
u get.... 1-2+3=5A
A=2/5

now u consider coefficients of x^2
x^2 = Ax^2 + Bx^2
1=A+B
A=2/5 therefore, B=3/5

now finally, to get value of C.... you take coeff of x
-2x=2Ax-Bx+Cx
-2=2A-B+C
A=2/5 and B=3/5..... u replace in equation
C=-11/5

FINALLY its
2/5/x-1 + ((3/5)x - 11/5)/(x^2 +2x+2)

its kinda difficult to show here...... :( :( :( if u dont understand sthing still tell me.....
 
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ok sssoooo
x^2 -2x+3
(x-1)(x^2 +2x+2) is equal to A/(x-1) + (Bx + c)/(x^2 + 2X + 2)

so if we take an LCM of (x-1)(x^2 +2x+2)
the numerators are
A(x^2 +2x+2) + (Bx +C)(x-1)
these should be equal to the original numerators x^2 -2x+3
so its supposed to be

x^2 -2x+3 =A(x^2 +2x+2) + (Bx +C)(x-1)
now we take x=1 to eliminate Bx+C
u get.... 1-2+3=5A
A=2/5

now u consider coefficients of x^2
x^2 = Ax^2 + Bx^2
1=A+B
A=2/5 therefore, B=3/5

now finally, to get value of C.... you take coeff of x
-2x=2Ax-Bx+Cx
-2=2A-B+C
A=2/5 and B=3/5..... u replace in equation
C=-11/5

FINALLY its
2/5/x-1 + ((3/5)x - 11/5)/(x^2 +2x+2)

its kinda difficult to show here...... :( :( :( if u dont understand sthing still tell me.....
thankoooooo ab ye akhri term ko integrate ... ((3/5)x - 11/5)/(x^2 +2x+2) plz
 
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dude.. i dun want u to expand... integrate this.... or may be now we will substitute
 
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i think i think i think....
x^2 +2x +2
can be said as (x+1)^2 +1 let x+1 be u
u^2 +1 can be done with the formula... 1/a tan inverse (x/a)
 
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i think i think i think....
x^2 +2x +2
can be said as (x+1)^2 +1 let x+1 be u
u^2 +1 can be done with the formula... 1/a tan inverse (x/a)
but x^2 +2x +2 is not equal to (x+1)^2......
try to expand (x+1)^2.... u wont get x^2 + 2x + 2
 
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