HALPPPP! IM DYING!!!!!!!!!1

[Rutzaba]

but x^2 +2x +2 is not equal to (x+1)^2......
try to expand (x+1)^2.... u wont get x^2 + 2x + 2

see again... (x+1)^2 +1 there is a plus one too

 

[Steel Arm]

see again... (x+1)^2 +1 there is a plus one too

yep u rite once more..... srry miread tht again

 

[Rutzaba]

yep u rite once more..... srry miread tht again

y so sad? u jjust proved ur self a math genius by helping me out thnks... stop being an emo

 

[Steel Arm]

y so sad? u jjust proved ur self a math genius by helping me out thnks... stop being an emo

lol..... maths genius??? LOL
ok ok....

 

[Rutzaba]

lol..... maths genius??? LOL
ok ok....

 

[Rutzaba]

hey!!!!!! i got the right answer... it is now that i get time to sit and solve it... thankyou Steel Arm

 

[Steel Arm]

Wow - Congrats!!!!!!

 

[Rutzaba]

Wow - Congrats!!!!!!

i need ur help again plz... reply asap...
just do the necessary partial fractions... id be ever grateful

 

[Rutzaba]

Q)1 ((x^3)+1) / (((x^2) -2)^2)
that meas x cube plus one in the numerator... and the square of x square minus 2 in the denominator

 

[Rutzaba]

Q)2 x cube minus two x square plus three x minus four ... in the numerator
and x square plus two x plus 2 multiplied by the whole square of x minus 1
lol
x^3 -2x^2 +3x -4
(x-1)^2 (x^2 +2x+2)

 

[Rutzaba]

badrobot14

 

[Scafalon40]

ahem... now can someone do the partial fractions in this and make this in a form i can integrate?

x^2 -2x+3
(x-1)(x^2 +2x+2)

please do the partial fractions clearly...

Ever heard of the boy who cried wolf?

 

[Rutzaba]

Ever heard of the boy who cried wolf?

i am addressing steel arm... u got a prob stay away from this thread.... im not in a good mood

 

[Scafalon40]

i am addressing steel arm... u got a prob stay away from this thread.... im not in a good mood

lol take it easy. I was just joking. no need to get all emotional! btw I quoted your first post

 

[Rutzaba]

lol take it easy. I was just joking. no need to get all emotional! btw I quoted your first post

its ok... i am not in a gud mood... not ur fault.

 

[Scafalon40]

its ok... i am not in a gud mood... not ur fault.

There now. No harm done.

 

[Steel Arm]

ok..... srry for late reply...... but got bad news....
1st one.
i really dont know what to do here... i mean, is it not already in partial fractions???
for 2nd one
OK i've never done such a partial fraction.... i'm not sure its good....... but i tried here......
i'll do the main work, u finish it all.....
by using the A, B, Cx + D thing u get this
A(x^2 + 2x + 2)(x-1) + B(x^2 + 2x + 2) + (Cx+D)((x-1)^2) for the numerator.....
now compare coefficients and all
u get all these equations!!!!
for x^3 ----> A+C=1
for x^2 -----> A+B+D-2C = -2
for x -------> 2B+C-2D = 3

now, u can eliminate x-1 by letting x =1
u will get B=-2/5

now if you let x=0, u get this equation
-2A+2B+D=-4
u replace B here.....
-2A+D = 24/5


now big task is solving AALLL these equationS!!!!!
ok firstly replace B in coeff of x equation.....
u get this C=2D+19/5
Replace this C in x^3 equation
u get an eqaution in terms of A and D
Now remember tht red equation as well is in terms of A and D
u solve these 2 and get the values of A and D
and the rest u just replace the values u get.....

Srry for late reply....

 

[Rutzaba]

dun wrry yar... mindu the answrs are weird like 7/50 and 18/25 likethat...
the only reason i dunno how to do em is cux tese arennt in the a levels syllabus....

 

[Rutzaba]

ok..... srry for late reply...... but got bad news....
1st one.
i really dont know what to do here... i mean, is it not already in partial fractions???
for 2nd one
OK i've never done such a partial fraction.... i'm not sure its good....... but i tried here......
i'll do the main work, u finish it all.....
by using the A, B, Cx + D thing u get this
A(x^2 + 2x + 2)(x-1) + B(x^2 + 2x + 2) + (Cx+D)((x-1)^2) for the numerator.....
now compare coefficients and all
u get all these equations!!!!
for x^3 ----> A+C=1
for x^2 -----> A+B+D-2C = -2
for x -------> 2B+C-2D = 3

now, u can eliminate x-1 by letting x =1
u will get B=-2/5

now if you let x=0, u get this equation
-2A+2B+D=-4
u replace B here.....
-2A+D = 24/5


now big task is solving AALLL these equationS!!!!!
ok firstly replace B in coeff of x equation.....
u get this C=2D+19/5
Replace this C in x^3 equation
u get an eqaution in terms of A and D
Now remember tht red equation as well is in terms of A and D
u solve these 2 and get the values of A and D
and the rest u just replace the values u get.....

Srry for late reply....

atleast u helped thankuuuuuuuuuuuuuuuuuuuuuu

 

[syed1995]

If you don't mind me asking.. where are these questions from..? If I know where they are from.. I might be able to help you better...

((x^3)+1) / (((x^2) -2)^2)

That's already simplified... can't simplify it more..