Mathematics: Post your doubts here!

[applepie1996]

thank you very much

and one thing : how do we know that the accelerations in the blue parts are both same? for both particles?

that is because they both have the same speeds so same acceleration

 

[Rutzaba]

please help me with question number 10(iii) with a bit of explanation . The link to the question papers is : http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_32.pdf

we had this paper the year i sat my cie y it be so idiotic...
anyways

 

[Silent Hunter]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_41.pdf


How to do question 5 (ii) ?

Is the work done = 0 ? if yes? then why ?

 

[applepie1996]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_41.pdf


How to do question 5 (ii) ?

Is the work done = 0 ? if yes? then why ?

wait i will do in a moment

 

[salvatore]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_ms_61.pdf
Qn no. 7 - whole question.
Please help me solve the question above.. I'm totally confused!

 

[unseen95]

we had this paper the year i sat my cie y it be so idiotic...
anyways

please answer it for me its killing me

 

[Rutzaba]

please answer it for me its killing me

i did this halfway only and attempting this wud break ma heart yet again... i think sumone else shud try it
il give u a hint... to find out perpendicular distance from one point to one plane we use the formula given in the question

where a b and c are where the point starts that is the coordinates of p... and x y and z wud be the normal coordinates
find two such equations one with m and one with n and equate them with each other

 

[A star]

we had this paper the year i sat my cie y it be so idiotic...
anyways

i am soo glad i am not giving p3 till next year. s1 is killing me and i heard p3 is even tougher

 

[A star]

in some question where equation comes down to 1.3^n=39 or zomething to solve it if we use logs will it given credit?

 

[Abu mota]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_43.pdf Q.4
Also: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_43.pdf
Q.6 ii and Q.7 ii and iii

plz help me

 

[unseen95]

i did this halfway only and attempting this wud break ma heart yet again... i think sumone else shud try it
il give u a hint... to find out perpendicular distance from one point to one plane we use the formula given in the question

where a b and c are where the point starts that is the coordinates of p... and x y and z wud be the normal coordinates
find two such equations one with m and one with n and equate them with each other

thanks it helped

 

[Rutzaba]

thanks it helped

u did it?

 

[Rutzaba]

i am soo glad i am not giving p3 till next year. s1 is killing me and i heard p3 is even tougher

its not tough.. its just that we had never seen this kind of questions ever before

 

[Rutzaba]

depends on u... i loved p3 as compared to s1.
ii gave accelerated... and u wont guess.... with s2
got a b :/
and that also after only two months study of s2

 

[applepie1996]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w12_qp_33.pdf
question 7 please

 

[applepie1996]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_41.pdf


How to do question 5 (ii) ?

Is the work done = 0 ? if yes? then why ?

ummmm.........the work done isn't equal to zero
because the object moves through a distance with an applied force

 

[ahmed abdulla]

can any one help me with mj 2010 varient 13 ... p1 ... q 8(ii) ??????

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_13.pdf

 

[applepie1996]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf
question 7 please

its okay i got it
no need to do it

 

[Rutzaba]

ok here goes to find the limits of this curve y= sin cube 2x cos cube 2x we will put y=0 as on the x axis y=o
0= cos cube2x sin cube 2x o=sin cube 2x
sin cube 2x = 0 0 = cos cube 2x
x=0 2x=pi/2

x= pi/4

so the limits be pi/4 and 0

by substituting u= sin2x
du/dx = 2cos2x
du= 2cos2x dx

now substituting

(cos cube 2x)( u^3) (1/ 2cos2x) <----------- where this is du
one cos would be cut by the cos in the denominator
u^3 (cos square 2x)/2
remember that cos square x = 1-sin square x
so cos square x = 1-sin square x
so
cos square 2x = 1-sin square 2x
and sin 2x =u
so
cos square 2x= 1- u^2
then the total thing wud be
1/2 integral of u^3(1-u^2)
1/2 integral of u^3 - u^5
1/2 (( u^4)/4 - (u^6)/6)
now open u as sin2x
1/2 (( sin 2x^4)/4 - (sin 2x^6)/6)
1/2 (1/4- 1/6)
1/2 (1/12)
1/24

 

[Rutzaba]

its okay i got it
no need to do it

u did a bad thing