• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Messages
1,824
Reaction score
949
Points
123
Please answer this question
For a biased cubical dice the probability of any particular score between 1 and 6 (inclusive) being obtained is inversely proportional to that score. Find the probability of scoring a 1.

I don't know .. I think this is what it will be... What's the answer?

1 ----- 2 ----- 3 ---- 4 ---- 5 ---- 6
x/1 + x/2 + x/3+ x/4 + x/5 + x/6 = 1

49x/20 = 1
x = 20/49


Probability of 1 = x/1
= 20/49 Answer
 
Messages
2,703
Reaction score
3,939
Points
273
I don't know .. I think this is what it will be... What's the answer?

1 ----- 2 ----- 3 ---- 4 ---- 5 ---- 6
x/1 + x/2 + x/3+ x/4 + x/5 + x/6 = 1

49x/20 = 1
x = 20/49


Probability of 1 = x/1
= 20/49 Answer
what i thought at first thought but i dont know if it is rite :confused:
 
Messages
2,703
Reaction score
3,939
Points
273
Messages
2
Reaction score
1
Points
3
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w08_qp_3.pdf

question no. 9 please please please help :/

and

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_3.pdf


question number 6

The parametric equations of a curve are
x = a cos^3 t, y = a sin^3 t,
where a is a positive constant and 0 < t < pie/2
(i) Express dy/dx in terms of t. [3]
(ii) Show that the equation of the tangent to the curve at the point with parameter t is
x sin t + y cos t = a sin t cos t.

I've done part one. How do you do part (ii) ?

please help! Thanks in advance :)
 
Messages
2,703
Reaction score
3,939
Points
273
can anyone help me by telling me how to find out angle between tangents and angle between tangents and x axis :/. for some reason i keep forgetting
 
Messages
2,703
Reaction score
3,939
Points
273
Messages
11
Reaction score
1
Points
13
5 The weights of letters posted by a certain business are normally distributed with mean 20 g. It is
found that the weights of 94% of the letters are within 12 g of the mean.
(i) Find the standard deviation of the weights of the letters. [3]

Could someone please answer this and show ALL the steps? Thank you :)
 

Dug

Messages
227
Reaction score
515
Points
103
5 The weights of letters posted by a certain business are normally distributed with mean 20 g. It is
found that the weights of 94% of the letters are within 12 g of the mean.
(i) Find the standard deviation of the weights of the letters. [3]

Could someone please answer this and show ALL the steps? Thank you :)
__8(µ-12)____20(µ)____32(µ+12)__

P(8 > X > 32) = 0.94
P(X < 8) = P(X > 32) = 0.03

P(Z < -12/σ) = 0.03
1 - φ(12/σ) = 0.03
φ(12/σ) = 0.97
12/σ = 1.881
σ = 6.38
 
Messages
1,601
Reaction score
553
Points
123
okay so here goes :D

so the equation is 2 tan2x + 5 tan^2 x = 0 --------- (1)
you open up tan2x = 2tanx/1-tan^2 x
now substitute this in the equation numbered (1) and you get .......
2 ( 2tanx/1-tan^2 x ) + 5 tan^2 x = 0-----------(2)
now since the question says use tanx as "t" substitute tanx as t in equation (2)
so you get , 2( 2t / 1- t^2 ) + 5 t^2 = 0
then open up the bracket and remove the fraction by multiplying the whole equation with 1-t^2 you get........
4t + 5t^2 - 5t^4 = 0
take "t" as a common factor and you get .........
t(4 + 5t - 5t^3) = 0
so t=0 and 4 + 5t - 5t^3=0-----------3
rearrange equation 3 as 5t^3=4+5t then divide equation by 5 ............you get
t^3=0.8+t and then cube root the other side :D
and wallah.............you get the answer :p
 
Messages
124
Reaction score
343
Points
73
can anyone help me by telling me how to find out angle between tangents and angle between tangents and x axis :/. for some reason i keep forgetting
You need to find the gradients of both the tangents, and then use the formula: tan-1[m2-m1/1-(m2*m1)]
(where m2 and m1 are the gradients, and m2 is the bigger grad.)
 
Top