Q1 is easy
part i) tan (180 - x) = -tan x since pie = 180 we can see
tan (pi- x) = -k
part ii) tan(90- x)= 1/tanx so use it to get 1/k
for last part u know tan x = perp/base therefore
perpendicular = k
base = 1
hypotenuse = underroot(k^2 +1) hense sin x =perp/hypotenuse ull get the anser