Mathematics: Post your doubts here!

[applepie1996]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s08_qp_3.pdf
sum1 help with Q9ii.... Dug syed1995

okay so i will try to do it

 

[applepie1996]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s08_qp_3.pdf
sum1 help with Q9ii.... Dug syed1995

ok so you i am assuming you know that to find the integration of the volume you multiply the equation with pi and square it
so you get (pi) [(e^(-1/2)x)(sqrt(1+2x))^2 then you get pi e^-x (1+2x)
after you get that equation
you integrate it
so integartion of pi e^-x (1+2x) gives
oh and make sure you integrate by parts as there is no other way

 

[syed1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s08_qp_3.pdf
sum1 help with Q9ii.... Dug syed1995

Don't have P3.

 

[Farhan Chowdhury]

__8(µ-12)____20(µ)____32(µ+12)__

P(8 > X > 32) = 0.94
P(X < 8) = P(X > 32) = 0.03

P(Z < -12/σ) = 0.03
1 - φ(12/σ) = 0.03
φ(12/σ) = 0.97
12/σ = 1.881
σ = 6.38

THANK YOU SO MUCH!!
could you please explain why P(X < 8) = P(X > 32) = 0.03?

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s08_qp_3.pdf
sum1 help with Q9ii.... Dug syed1995

http://i1275.photobucket.com/albums/y444/Rutzaba/mind_zpsa77f0ef6.png

 

[tompapaya]

questions about pure math 1
i do not have any ideas about this kinds of questions.
could u give me some help? thanks a lot!

 

[tompapaya]

QUESTION abt statistics!
how abt the question 3?
HELP!pls!

 

[salvatore]

dude the curve you have drawn is completely wrong for one thing its axis is y=4 and amplitude is clearly 3 . hence redraw the curve and get the correct answer

Yeah.. I figured it out. Thanks

 

[Rutzaba]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s08_qp_3.pdf
sum1 help with Q9ii.... Dug syed1995

did u get it? or u just liked it?

 

[Dug]

THANK YOU SO MUCH!!
could you please explain why P(X < 8) = P(X > 32) = 0.03?

The distribution curve is symmetrical about its mean which is 20.
Total area under any normal distribution curve = 1

In the above sketch, if the yellow area = 0.94,
P(X < µ-2σ) = P(X > µ+2σ) = 0.3

 

[Farhan Chowdhury]

The distribution curve is symmetrical about its mean which is 20.
Total area under any normal distribution curve = 1

In the above sketch, if the yellow area = 0.94,
P(X < µ-2σ) = P(X > µ+2σ) = 0.3

THANK YOU SOOO MUCH XD

 

[istudent]

Please help
1-tan2x/1+tan2x=1-2sin2x
prove the identity

 

[unseen95]

please help me with 10(iii) and (iv). Link to the question paper: http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_31.pdf

 

[VelaneDeBeaute]

please help me with 10(iii) and (iv). Link to the question paper: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_31.pdf

For Q.10.iii., it's the usage of the iteration formula simply. The root lies between 1.2 and 1.3, so let's assume it is 1.25. Now
Tn =T1= 1.25
Use the formula given to calculate further T(n+1) values
T2 = 1.2703
T3 = 1.2745
T4 = 1.2745
T5 = 1.2756
T6 = 1.2756
At this point, you see that the iteration has converged successfully. Hence, the value of the root is 1.276 (correct to 3 decimal places).
(If you're unsure about the concept then refer to this http://www.examsolutions.net/maths-...erical-methods/roots/iteration/tutorial-1.php)

For Q.10.iv., you just use the value found for t, that is, 1.276 and solve the equation. But before that, simplify the equation, especially the part in tan 2x.

 

[VelaneDeBeaute]

Please help
1-tan2x/1+tan2x=1-2sin2x
prove the identity

I doubt your question. Are you sure there are no powers in there?

 

[tanzzz]

i wanted to know that do we get a formula sheet during the exam of mathematics in AS levels!!!

 

[unseen95]

For Q.10.iii., it's the usage of the iteration formula simply. The root lies between 1.2 and 1.3, so let's assume it is 1.25. Now
Tn =T1= 1.25
Use the formula given to calculate further T(n+1) values
T2 = 1.2703
T3 = 1.2745
T4 = 1.2745
T5 = 1.2756
T6 = 1.2756
At this point, you see that the iteration has converged successfully. Hence, the value of the root is 1.276 (correct to 3 decimal places).
(If you're unsure about the concept then refer to this http://www.examsolutions.net/maths-...erical-methods/roots/iteration/tutorial-1.php)

For Q.10.iv., you just use the value found for t, that is, 1.276 and solve the equation. But before that, simplify the equation, especially the part in tan 2x.

thanks for the help

 

[Alice123]

did u get it? or u just liked it?

I got it... thanks

 

[unseen95]

please help me with question number 10(iii) with a bit of explanation . The link to the question papers is : http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_32.pdf

 

[Silent Hunter]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s06_qp_4.pdf

help required in this paper

its Mechanics 1 ... question 7 ?