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AS Chemistry Question

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According to Le Chatelier's principle for gases, increasing the pressure would cause the equilibrium to shift to the side with fewer molecules but what if the side that we increase pressure on already has fewer molecules then the other side???......
 
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According to Le Chatelier's principle for gases, increasing the pressure would cause the equilibrium to shift to the side with fewer molecules but what if the side that we increase pressure on already has fewer molecules then the other side???......
According to the principle the reaction will again shift towards the reactants
 
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down the group 2... what happens to the cationic size, anionic size and the charge density?? .plz help
 
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According to Le Chatelier's principle for gases, increasing the pressure would cause the equilibrium to shift to the side with fewer molecules but what if the side that we increase pressure on already has fewer molecules then the other side???......
you increase the pressure on the whole reaction not on a specific side
 
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down the group 2... what happens to the cationic size, anionic size and the charge density?? .plz help
cat size increases down the group which means the same nuclear charge is distributed over a larger volume hence the charge density decreases
 
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down the group 2... what happens to the cationic size, anionic size and the charge density?? .plz help
Down group two the cation size would decrease. This is because as we go down and elements loose electrons the remaining electrons are attracted more strongly by the nucleus causing the ionic radius to decrease.
The anion size across a period would increase. This is because as we go across the period elements gain more electrons and the -ve charges (electrons) out number the +ve charges (protons) thus the elements gains a -ve charge. The nucleus would not be able to attract more electrons thus the ionic radius would increase....
 
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Down group two the cation size would decrease. This is because as we go down and elements loose electrons the remaining electrons are attracted more strongly by the nucleus causing the ionic radius to decrease.
The anion size across a period would increase. This is because as we go across the period elements gain more electrons and the -ve charges (electrons) out number the +ve charges (protons) thus the elements gains a -ve charge. The nucleus would not be able to attract more electrons thus the ionic radius would increase....
noooo this is if u compare the ion to its element but the cation size decreases as u go down the group because as u go down u gain an extra shell
 
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According to Le Chatelier's principle for gases, increasing the pressure would cause the equilibrium to shift to the side with fewer molecules but what if the side that we increase pressure on already has fewer molecules then the other side???......
You can't increase the pressure of a single side...

Down group two the cation size would decrease. This is because as we go down and elements loose electrons the remaining electrons are attracted more strongly by the nucleus causing the ionic radius to decrease.
The anion size across a period would increase. This is because as we go across the period elements gain more electrons and the -ve charges (electrons) out number the +ve charges (protons) thus the elements gains a -ve charge. The nucleus would not be able to attract more electrons thus the ionic radius would increase....

The cation size doesn't decrease down the group... They increase, so does the anion size.
I believe what you meant was that cationic radii are shorter than their parent atoms', and anionic radii are greater than their parent atoms'.
 
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You can't increase the pressure of a single side...



The cation size doesn't decrease down the group... They increase, so does the anion size.
I believe what you meant was that cationic radii are shorter than their parent atoms', and anionic radii are greater than their parent atoms'.
You can't increase the pressure of a single side...



The cation size doesn't decrease down the group... They increase, so does the anion size.
.
down the group the cationic radius increases,because the number of shells increases,hence the e- are removed from the outer most shell.
across a period the cationic size decreases because,moving across a period the number of shells doesnot increase and the e- is removed from the same shell therefore nucleus to e- attraction increases resulting in a decrease in the size
 
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down the group the cationic radius increases,because the number of shells increases,hence the e- are removed from the outer most shell.
across a period the cationic size decreases because,moving across a period the number of shells doesnot increase and the e- is removed from the same shell therefore nucleus to e- attraction increases resulting in a decrease in the size
That's what I said :D
 
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Down group two the cation size would decrease. This is because as we go down and elements loose electrons the remaining electrons are attracted more strongly by the nucleus causing the ionic radius to decrease.
The anion size across a period would increase. This is because as we go across the period elements gain more electrons and the -ve charges (electrons) out number the +ve charges (protons) thus the elements gains a -ve charge. The nucleus would not be able to attract more electrons thus the ionic radius would increase....

can u check plz.. cuz. read post #5 :p
 
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