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Mathematics: Post your doubts here!

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Any Help>
a beetle starts from o and walk 0.6 m east and then 0.36 m west and then 0.216 east and so on ..
find its final position .. its a GP
 
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yep bro its correct!!
how did you get it? or was it a guess? :p
LOL no, not a guess :p
Basically, for question like this put a negative sign for the opposite direction. Doing this the geometric progression becomes: 0.6, -0.36, 0.216 ... where ratio r is (-.36/.6) = -3/5. In this case, r is less than 1 so the formula used for the sum would be
[a(1/r^n)]/1-r
Take n to be infinite, which means r^∞ approaches to 0.
[0.6(1-0)]/ 1-(-3/5) = 0.6/1.6 = 0.375. As the answer is +ve, we take it to be towards the East.
 
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LOL no, not a guess :p
Basically, for question like this put a negative sign for the opposite direction. Doing this the geometric progression becomes: 0.6, -0.36, 0.216 ... where ratio r is (-.36/.6) = -3/5. In this case, r is less than 1 so the formula used for the sum would be
[a(1/r^n)]/1-r
Take n to be infinite, which means r^∞ approaches to 0.
[0.6(1-0)]/ 1-(-3/5) = 0.6/1.6 = 0.375. As the answer is +ve, we take it to be towards the East.
i hope same question comes tomorrow .. just pray hh
thanks
 

Dug

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I need help with this question. If anyone could please explain, I'd be grateful.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_33.pdf
Q6 (i). tan3x = ktanx where k is a constant and tanx ≠0.
By first expanding tan(2x + x), show that (3k-1)tan^2(x) = k-3
It's simple trigonometry, I know, but I can not come up with the expression they've given :/
gqbKt89.jpg
 
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Dug Thankyou so much! I see I wasn't doing it wrong, but made it so messy that stuck half way through it.
 
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