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IGCSE Maths Paper 42
- Thread starter lklk123
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got it..thnkss
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Anytime 
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it is an equilateral triangle forming with all of the tree trunks covered by plastic!!
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf can u plzz let me knw hw to solve question no 7 part (a) 2...
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a (i)...(2/5)*(1/4) = 2/20
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(4 and 1) or (1 and 4) or (3 and 2) or (2 and 3)
or means + so
(1/5*1/4) + (1/5*1/4) + (1/5*2/4) + (2/5*1/4)
(1/20) + (1/20) + (2/20) + (2/20) = 6/20
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http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf hw 2 solve question 8 part (c) ??
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Hello .. can anyone explain for me shear and Stretch with diagrams and how to find it's scale factors because I cant do any question in the past papers related to this TOPIC and link any website which help to teach them
Thank's a lot
and link any website which help to teach them Thank's a lot
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Answer (a): 2/5 x 1/4
=2/20
Answer (b): 1&4, 4&1, 3&2, 2&3...
= 2(1/5 x 1/4) + 2(1/5x2/4)
=2/20 + 4/20
=6/20
Answer (c): 1- 6/20
=14/20
Hope this helps!
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area of triangle - area of the sector
you have to find LM first by SOHCAHTOA = 8 tan 44 = 7.73
(1/2*7.73*8) - (44/360*3.142*8^2)
= 6.34
hope this helps
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I hate transformations too..
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Transformations are free marks for me xD Easy
Answer (a): 2/5 x 1/4
=2/20
Answer (b): 1&4, 4&1, 3&2, 2&3...
= 2(1/5 x 1/4) + 2(1/5x2/4)
=2/20 + 4/20
=6/20
Answer (c): 1- 6/20
=14/20
Hope this helps!
Tnxs a billion...
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anytimetnxs a billion....
First of all find de area of de sector using de formulae.....
den u knw dat any tangent to de circle forms 90 degree wid de radius.....therefore now u can use the pythagorean theorem to find de length LM...
ummmm den now u find de area of de right angle triangle........ aftr finding dat subtract de area of de sectr wid de area of triangle to find de shaded area....
Hope dis ws helpful...cheese..