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It's easy...Q 5b (i)
5(x+2)+6x=x(x+2)
5x+10+6x=x*x+2x
0=x*x-9x-10
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It's easy...Q 5b (i)
how will it form an equilateral triangle??
a (i)...(2/5)*(1/4) = 2/20http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf can u plzz let me knw hw to solve question no 7 part (a) 2...
(4 and 1) or (1 and 4) or (3 and 2) or (2 and 3)http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf can u plzz let me knw hw to solve question no 7 part (a) 2...
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf can u plzz let me knw hw to solve question no 7 part (a) 2...
area of triangle - area of the sectorhttp://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf hw 2 solve question 8 part (c) ??
I hate transformations too..How did you guys find Paper 2?
I really hope Paper 4 wont be that hard, I hope transformations wont come! I hate that stuff :s
(4 and 1) or (1 and 4) or (3 and 2) or (2 and 3)
or means + so
(1/5*1/4) + (1/5*1/4) + (1/5*2/4) + (2/5*1/4)
(1/20) + (1/20) + (2/20) + (2/20) = 6/20
Answer (a): 2/5 x 1/4
=2/20
Answer (b): 1&4, 4&1, 3&2, 2&3...
= 2(1/5 x 1/4) + 2(1/5x2/4)
=2/20 + 4/20
=6/20
Answer (c): 1- 6/20
=14/20
Hope this helps!
anytimetnxs a billion....
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf hw 2 solve question 8 part (c) ??
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